1
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

General solution of the differential equation $$\cos x(1+\cos y) \mathrm{d} x-\sin y(1+\sin x) \mathrm{d} y=0$$ is

A
$$(1+\cos x)(1+\sin y)=\mathrm{c}$$, where $$\mathrm{c}$$ is a constant of integration.
B
$$1+\sin x+\cos y=\mathrm{c}$$, where $$\mathrm{c}$$ is a constant of integration.
C
$$(1+\sin x)(1+\cos y)=\mathrm{c}$$, where $$\mathrm{c}_{\text {is }}$$ constant of integration.
D
$$1+\sin x \cos y=\mathrm{c}$$, where $$\mathrm{c}$$ is a constant of integration.
2
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The money invested in a company is compounded continuously. If ₹ 200 invested today becomes ₹ 400 in 6 years, then at the end of 33 years it will become ₹

A
$$1600 \sqrt{2}$$
B
$$3200 \sqrt{2}$$
C
$$12800 \sqrt{2}$$
D
$$6400 \sqrt{2}$$
3
MHT CET 2023 14th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of $$y=\mathrm{e}^x(\mathrm{a} \cos x+\mathrm{b} \sin x)$$ is

A
$$\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}-y=0$$
B
$$\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}+2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0$$
C
$$\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+y=0$$
D
$$\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}-2 \frac{\mathrm{d} y}{\mathrm{~d} x}+2 y=0$$
4
MHT CET 2023 13th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$x d y=y(d x+y d y), y(1)=1, y(x)>0$$, then $$y(-3)$$ is

A
1
B
2
C
3
D
4

MHT CET Subjects

Browse all chapters by subject