1
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The integrating factor of the differential equation $x \frac{\mathrm{~d} y}{\mathrm{~d} x}+y \log x=x \cdot \mathrm{e}^x x^{-\frac{1}{2}} \log x(x>0)$ is

A

$\quad(\log x)^x$

B

$x^{\log x}$

C

$(\sqrt{x})^{\log x}$

D

$e^{\sqrt{x} \log x}$

2
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The equation of the curve passing through the point $(0,2)$ given that the sum of the ordinate and abscissa of any point exceeds the slope of the tangent to the curve at that point by 5 is

A

$y=x-4-2 \mathrm{e}^x$

B

$y=4-x-2 \mathrm{e}^x$

C

$y=4+x-2 \mathrm{e}^x$

D

$y=4-x+2 \mathrm{e}^x$

3
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The solution of the differential equation $(1+x) \frac{\mathrm{d} y}{\mathrm{~d} x}-x y=1-x$ is

A

$y(1+x)=x+\mathrm{ce}^x$, where c is the constant of integration

B

$\quad y(1+x)=\mathrm{ce}^x$, where c is the constant of integration

C

$y(1-x)=x-\mathrm{ce}^x$, where c is the constant of integration

D

$y(1+x)=x$, where c is the constant of integration

4
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation representing the family of parabolas having vertex at the origin and axis along the positive Y -axis is

A

$x \frac{\mathrm{~d} y}{\mathrm{~d} x}-2 y=0$

B

$\frac{\mathrm{d} y}{\mathrm{~d} x}+x y=0$

C

$\quad x \frac{\mathrm{~d} y}{\mathrm{~d} x}+y=0$

D

$x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+y=0$

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