1
MHT CET 2025 20th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation whose solution represents the family $x^2 y=4 \mathrm{e}^x+\mathrm{c}$, where c is an arbitrary constant, is

A
$\quad x \frac{\mathrm{~d} y}{\mathrm{~d} x}+x y=0$
B
$\quad x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+(2 x-x y)=0$
C
$x \frac{\mathrm{~d} y}{\mathrm{~d} x}+(x-2) y=0$
D
$x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+2 x y-4 \mathrm{e}^x=0$
2
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation of all straight lines passing through the point $(1,-1)$ is

A
$y=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}-1$
B
$x=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}+1$
C
$y=(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}$
D
$\quad y=2(x-1) \frac{\mathrm{d} y}{\mathrm{~d} x}$
3
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The principal increases continuously in a newly opened bank at the rate of $10 \%$ per year. An amount of Rs. 2000 is deposited with this bank. How much will it become after 5 years?

$$ \left(\mathrm{e}^{0.5}=1.648\right) $$

A
3926
B
3296
C
3692
D
3269
4
MHT CET 2025 19th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The solution of $\frac{\mathrm{d} y}{\mathrm{~d} x}=(x+y)^2$ is

A
$\tan ^{-1}(x+y)=x+\mathrm{c}$, where c is the constant of integration
B
$x+y=\tan x+\mathrm{c}$, where c is the constant of integration
C
$x+y=\cot ^{-1} x+\mathrm{c}$, where c is the constant of integration
D
$x+y=\sin ^{-1}(x+y)+\mathrm{c}$, where c is the constant of integration
MHT CET Subjects
EXAM MAP