JEE Advanced 2023 Paper 1 Online

MCQ (Single Correct Answer)

-1

Match the temperature of a black body given in List-I with an appropriate statement in List-II, and choose the correct option.

[Given: Wien's constant as $2.9 \times 10^{-3} \mathrm{~m}-\mathrm{K}$ and $\frac{h c}{e}=1.24 \times 10^{-6} \mathrm{~V}-\mathrm{m}$ ]

List - I	List - II
(P) $2000 \mathrm{~K}$	(1) The radiation at peak wavelength can lead to emission of photoelectrons from a metal of work function $4 \mathrm{eV}$.
(Q) $3000 \mathrm{~K}$	(2) The radiation at peak wavelength is visible to human eye.
(R) $5000 \mathrm{~K}$	(3) The radiation at peak emission wavelength will result in the widest central maximum of a single slit diffraction.
(S) $10000 \mathrm{~K}$	(4) The power emitted per unit area is $1 / 16$ of that emitted by a blackbody at temperature $6000 \mathrm{~K}$.
	(5) The radiation at peak emission wavelength can be used to image human bones.

$P \rightarrow 3, Q \rightarrow 5, R \rightarrow 2, S \rightarrow 3$

$P \rightarrow 3, Q \rightarrow 2, R \rightarrow 4, S \rightarrow 1$

$P \rightarrow 3, Q \rightarrow 4, R \rightarrow 2, S \rightarrow 1$

$P \rightarrow 1, Q \rightarrow 2, R \rightarrow 5, S \rightarrow 3$

JEE Advanced 2022 Paper 2 Online

MCQ (Single Correct Answer)

-1

When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is $6.0 \mathrm{~V}$. This potential drops to $0.6 \mathrm{~V}$ if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively? [Take $\frac{h c}{e}=1.24 \times$ $10^{-6} \mathrm{JmC}^{-1}$.]

$1.72 \times 10^{-7} \mathrm{~m}, 1.20 \mathrm{eV}$

$1.72 \times 10^{-7} \mathrm{~m}, 5.60 \mathrm{eV}$

$3.78 \times 10^{-7} \mathrm{~m}, 5.60 \mathrm{eV}$

$3.78 \times 10^{-7} \mathrm{~m}, 1.20 \mathrm{eV}$

JEE Advanced 2017 Paper 2 Offline

MCQ (Single Correct Answer)

-0.75

A photoelectric material having work-function $${\phi _0}$$ is illuminated with light of wavelength $$\lambda \left( {\lambda < {{he} \over {{\phi _0}}}} \right).$$ The fastest photoelectron has a de-Broglic wavelength $${\lambda _d}.$$ A change in wavelength of the incident light by $$\Delta \lambda $$ result in a change $$\Delta {\lambda _d}$$ in $${\lambda _d}.$$ Then the ratio $$\Delta {\lambda _d}/\Delta \lambda $$ is proportional to

$${\lambda _d}/\lambda $$

$$\lambda _d^2/{\lambda ^2}$$

$$\lambda _d^3/\lambda $$

$$\lambda _d^3/{\lambda ^2}$$

JEE Advanced 2016 Paper 1 Offline

MCQ (Single Correct Answer)

-1

In a historical experiment to determine Planck's constant, a metal surface was irradiated with light of different wavelengths. The emitted photoelectron energies were measured by applying a stopping potential. The relevant data for the wavelength ($$\lambda $$) of incident light and the corresponding stopping potential (V₀) are given below: