1
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
Let $\bar{a} = \hat{i} + \hat{j}$, $\bar{c} = \hat{i} - \hat{j}$ and a vector $\bar{b}$ be such that $\bar{a} \times \bar{b} = \bar{c}$ and $\bar{a} \cdot \bar{b} = 3$ then $|\bar{b}| =$
A
$\dfrac{11}{\sqrt{2}}$
B
$\dfrac{11}{\sqrt{3}}$
C
$\sqrt{\dfrac{11}{2}}$
D
$\sqrt{\dfrac{11}{3}}$
2
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The acute angle between the vector $2\hat{i} + \hat{j} - 3\hat{k}$ and the plane containing the vectors $2\hat{i} + 3\hat{j} - \hat{k}$ and $\hat{i} - \hat{j} + 2\hat{k}$ is
A
$\sin^{-1}\left(\dfrac{4}{\sqrt{42}}\right)$
B
$\cos^{-1}\left(\dfrac{4}{\sqrt{42}}\right)$
C
$\sin^{-1}\left(\dfrac{3}{\sqrt{42}}\right)$
D
$\cos^{-1}\left(\dfrac{3}{\sqrt{42}}\right)$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
A parallelogram is constructed on $5\bar{a} + 2\bar{b}$ and $\bar{a} - 3\bar{b}$ as its adjacent sides, with $|\bar{a}| = 2\sqrt{2}, |\bar{b}| = 3$ . The angle between $\bar{a}$ and $\bar{b}$ is $\dfrac{\pi}{4}$ . Then the length of the diagonals of the parallelogram are
A
$15, \sqrt{593}$
B
$15,\ 593$
C
$225,\ 593$
D
$20,\ 593$
4
MHT CET 2026 15th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
A unit vector coplanar with $\hat{i} + \hat{j} + 2\hat{k}$ and $\hat{i} + 2\hat{j} + \hat{k}$ and perpendicular to $\hat{i} + \hat{j} + \hat{k}$ is
A
$\pm\dfrac{1}{\sqrt{3}}(\hat{i} + \hat{j} + \hat{k})$
B
$\pm\dfrac{1}{\sqrt{3}}(\hat{i} - \hat{j} + \hat{k})$
C
$\pm\dfrac{1}{\sqrt{2}}(\hat{j} - \hat{k})$
D
$\pm\dfrac{1}{\sqrt{2}}(\hat{j} + \hat{k})$

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