1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x)$ is a polynomial such that $f(x) = [f'(x)]^2$ and $f(2) = 0$, then $f(-2) = \ldots$
A
$1$
B
$-1$
C
$4$
D
$-4$
2
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The integrating factor of the differential equation $(1 + t^2) + \left(x - e^{\tan^{-1}t}\right)\dfrac{dt}{dx} = 0$ is
A
$e^{\tan^{-1}t}$
B
$-e^{\tan^{-1}t}$
C
$e^{-\tan^{-1}t}$
D
$-e^{-\tan^{-1}t}$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The degree of the differential equation obtained from the equation $(y - a)^2 = 4(x - b)$ [where $a$ and b are arbitrary constants] is
A
$1$
B
$2$
C
$3$
D
not defined
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The solution of the differential equation $\left(x + 2y^3\right)\dfrac{dy}{dx} - y = 0$ is
A
$x = (c + y^2)y$, where c is the constant of integration
B
$y = (c + y^2)x$, where c is the constant of integration
C
$x = (c + y)y$, where c is the constant of integration
D
$y = (c + x^2)$, where c is the constant of integration

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