1
JEE Advanced 2020 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1
Change Language
A small roller of diameter 20 cm has an axle of diameter 10 cm (see figure below on the left). It is on a horizontal floor and a meter scale is positioned horizontally on its axle with one edge of the scale on top of the axle (see figure on the right). The scale is now pushed slowly on the axle so that it moves without slipping on the axle, and the roller starts rolling without slipping. After the roller has moved 50 cm, the position of the scale will look like (figures are schematic and not drawn to scale) JEE Advanced 2020 Paper 1 Offline Physics - Rotational Motion Question 39 English
A
JEE Advanced 2020 Paper 1 Offline Physics - Rotational Motion Question 39 English Option 1
B
JEE Advanced 2020 Paper 1 Offline Physics - Rotational Motion Question 39 English Option 2
C
JEE Advanced 2020 Paper 1 Offline Physics - Rotational Motion Question 39 English Option 3
D
JEE Advanced 2020 Paper 1 Offline Physics - Rotational Motion Question 39 English Option 4
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Change Language
Consider regular polygons with number of sides $$n=3,4,5....$$ as shown in the figure. The center of mass of all the polygons is at height $$h$$ from the ground. They roll on a horizontal surface about the leading vertex without slipping and sliding as depicted. The maximum increase in height of the locus of the center of mass for each polygon is $$\Delta $$. Then $$\Delta $$ depends on $$n$$ and $$h$$ as

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 40 English
A
$$\Delta = h{\sin ^2}\left( {{\pi \over n}} \right)$$
B
$$\Delta = h\left( {{1 \over {\cos \left( {{\pi \over n}} \right)}} - 1} \right)$$
C
$$\Delta = h\sin \left( {{{2\pi } \over n}} \right)$$
D
$$\Delta = h\,{\tan ^2}\left( {{\pi \over {2n}}} \right)$$
3
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
Change Language
One twirls a circular ring (of mass M and radius R) near the tip of one's finger as shown in Figure 1. In the process the finger never loses contact with the inner rim of the ring. The finger traces out the surface of a cone, shown by the dotted line. The radius of the path traced out by the point where the ring and the finger is in contact is r. The finger rotates with an angular velocity $$\omega$$0. The rotating ring rolls without slipping on the outside of a smaller circle described by the point where the ring and the finger is in contact (Figure 2). The coefficient of friction between the ring and the finger is $$\mu$$ and the acceleration due to gravity is g.

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 27 English Comprehension
The total kinetic energy of the ring is
A
$$M\omega _0^2{(R - r)^2}$$
B
$${1 \over 2}M\omega _0^2{(R - r)^2}$$
C
$$M\omega _0^2{R^2}$$
D
$${1 \over 2}M\omega _0^2[{(R - r)^2} + {R^2}]$$
4
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
Change Language
One twirls a circular ring (of mass M and radius R) near the tip of one's finger as shown in Figure 1. In the process the finger never loses contact with the inner rim of the ring. The finger traces out the surface of a cone, shown by the dotted line. The radius of the path traced out by the point where the ring and the finger is in contact is r. The finger rotates with an angular velocity $$\omega$$0. The rotating ring rolls without slipping on the outside of a smaller circle described by the point where the ring and the finger is in contact (Figure 2). The coefficient of friction between the ring and the finger is $$\mu$$ and the acceleration due to gravity is g.

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 28 English Comprehension
The minimum value of $$\omega$$0 below which the ring will drop down is
A
$$\sqrt {{g \over {2\mu (R - r)}}} $$
B
$$\sqrt {{{3g} \over {2\mu (R - r)}}} $$
C
$$\sqrt {{g \over {\mu (R - r)}}} $$
D
$$\sqrt {{{2g} \over {\mu (R - r)}}} $$
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