1
GATE ECE 2018
MCQ (Single Correct Answer)
+1
-0.33
A function F(A, B, C) defined by three Boolean variables A, B and C when expressed as sum of products is given by

F = $$\overline A .\overline B .\overline C + \overline A .B.\overline C + A.\overline B .\overline C$$

where, $$\overline A$$, $$\overline B$$, and $$\overline C$$ are the complements of the respective variables. The product of sums (POS) form of the function F is
A
F = (A + B + C)(A + $$\overline B$$ + C)($$\overline A$$ + B + C)
B
F = ($$\overline A$$ + $$\overline B$$ + $$\overline C$$)($$\overline A$$ + B + $$\overline C$$)(A + $$\overline B$$ + $$\overline C$$)
C
F = (A + B + $$\overline C$$)(A + $$\overline B$$ + $$\overline C$$)($$\overline A$$ + B + $$\overline C$$)($$\overline A$$ + $$\overline B$$ + C)($$\overline A$$ + $$\overline B$$ + $$\overline C$$)
D
F = ($$\overline A$$ + $$\overline B$$ + C)($$\overline A$$ + B + C)(A + $$\overline B$$ + C)(A + B + $$\overline C$$)(A + B + C)
2
GATE ECE 2014 Set 2
MCQ (Single Correct Answer)
+1
-0.3
For an n - variable Boolean function maximum number of prime implicants is
A
2(n-1)
B
n/2
C
$${2^n}$$
D
2$$^{_{(n - 1)}}$$
3
GATE ECE 2014 Set 1
MCQ (Single Correct Answer)
+1
-0.3
The Boolean expression (X+Y)(X+$$\overline Y$$)+($$\overline {(X\overline Y ) + \overline X }$$ simplifies to
A
X
B
Y
C
XY
D
X+Y
4
GATE ECE 2013
MCQ (Single Correct Answer)
+1
-0.3
In the sum of products function f (x,y,z) = $$\sum {}$$m (2,3,4,5), the prime implicants are
A
$$\overline X \,Y,X\overline Y$$
B
$$\overline X \,Y,X\overline Y$$$$\overline Z ,X\overline Y Z$$
C
$$\overline X Y\overline Z$$,$$\overline X YZ,X\overline Y$$
D
$$\overline X Y\overline Z$$ ,$$\overline X YZ,X\overline Y$$$$\overline Z ,X\overline Y Z$$
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