The effect of current shunt feedback in an amplifier is to

The input resistance R_i of the amplifier shown in the figure is

Given
$${r_d} = 20K\Omega ,\,\,{I_{DSS}}\, = \,10mA,\,\,{V_P} = - 8V$$

Transconductance in milli-Siemens (mS) and voltage gain of the amplifier are respectively.

Given
$${r_d} = 20K\Omega ,\,\,{I_{DSS}}\, = \,10mA,\,\,{V_P} = - 8V$$

I_D and V_DS under DC conditions are respectively