1
GATE ECE 2005
MCQ (Single Correct Answer)
+2
-0.6
The derivative of the symmetric function drawn in Fig .1 will look like GATE ECE 2005 Signals and Systems - Miscellaneous Question 13 English
A
GATE ECE 2005 Signals and Systems - Miscellaneous Question 13 English Option 1
B
GATE ECE 2005 Signals and Systems - Miscellaneous Question 13 English Option 2
C
GATE ECE 2005 Signals and Systems - Miscellaneous Question 13 English Option 3
D
GATE ECE 2005 Signals and Systems - Miscellaneous Question 13 English Option 4
2
GATE ECE 2005
MCQ (Single Correct Answer)
+1
-0.3
The function x(t) is shown in Fig. Even and odd parts of a unit-step function u(t) are respectively. GATE ECE 2005 Signals and Systems - Miscellaneous Question 19 English
A
$${1 \over 2},\,{1 \over 2}x(t)$$
B
$$-{1 \over 2},\,{1 \over 2}x(t)$$
C
$${1 \over 2},\,-{1 \over 2}x(t)$$
D
$$-{1 \over 2},\,-{1 \over 2}x(t)$$
3
GATE ECE 2005
MCQ (Single Correct Answer)
+2
-0.6
A signal x(n)$$ = \sin ({\omega _0}\,n + \phi )$$ is the input to a linear time-invariant system having a frequency response $$H({e^{j\omega }})$$.If the output of the system is $$Ax(n - {n_0})$$, then the most general form of $$\angle H({e^{j\omega }})$$ will be
A
$$ - {n_0}{\omega _0} + \beta $$ for any arbitrary real $$\beta $$
B
$$ - {n_0}{\omega _0} + 2\pi k$$ for any arbitrary integer k
C
$${n_0}{\omega _0} + 2\pi k$$ for any arbitrary integer k
D
$$-{n_0}{\omega _0} + \phi $$
4
GATE ECE 2005
MCQ (Single Correct Answer)
+2
-0.6
For a signal x(t) the Fourier transform is X(f). Then the inverse Fourier transform of X(3f+2) is given by
A
$${1 \over 2}\,x\left( {{t \over 2}} \right){e^{j3\pi t}}$$
B
$${1 \over 3}\,x\left( {{t \over 3}} \right){e^{ - j4\pi t/3}}$$
C
$$3\,x(3t){e^{ - j4\pi t}}$$
D
$$x(3t + 2)$$
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