GATE ECE 2005 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

Match the following and choose the correct combination.

GROUP 1
E- continuous and aperiodic signal
F- continuous and periodic signal
G- discrete and aperiodic signal
H- discrete and periodic signal

Group 2
1- Fourier representation is continuous and aperiodic
2- Fourier representation is discrete and aperiodic
3- Fourier representation is continuous and periodic
4- Fourier representation is discrete and periodic

E -3, F - 2, G - 4, H -1

E -1, F - 3, G - 2, H - 4

E - 1, F - 2, G - 3, H -4

E -2, F - 1, G - 4, H -3

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The derivative of the symmetric function drawn in Fig .1 will look like GATE ECE 2005 Signals and Systems - Miscellaneous Question 14 English

GATE ECE 2005 Signals and Systems - Miscellaneous Question 14 English Option 1

GATE ECE 2005 Signals and Systems - Miscellaneous Question 14 English Option 2

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

For a signal x(t) the Fourier transform is X(f). Then the inverse Fourier transform of X(3f+2) is given by

$${1 \over 2}\,x\left( {{t \over 2}} \right){e^{j3\pi t}}$$

$${1 \over 3}\,x\left( {{t \over 3}} \right){e^{ - j4\pi t/3}}$$

$$3\,x(3t){e^{ - j4\pi t}}$$

$$x(3t + 2)$$

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

A signal x(n)$$ = \sin ({\omega _0}\,n + \phi )$$ is the input to a linear time-invariant system having a frequency response $$H({e^{j\omega }})$$.If the output of the system is $$Ax(n - {n_0})$$, then the most general form of $$\angle H({e^{j\omega }})$$ will be

$$ - {n_0}{\omega _0} + \beta $$ for any arbitrary real $$\beta $$

$$ - {n_0}{\omega _0} + 2\pi k$$ for any arbitrary integer k

$${n_0}{\omega _0} + 2\pi k$$ for any arbitrary integer k

$$-{n_0}{\omega _0} + \phi $$

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