GATE ECE 2005 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

Given
$${r_d} = 20K\Omega ,\,\,{I_{DSS}}\, = \,10mA,\,\,{V_P} = - 8V$$ GATE ECE 2005 Analog Circuits - FET and MOSFET Question 25 English

I_D and V_DS under DC conditions are respectively

5.625 mA and 8.75 V

7.500 mA and 5.00V

4.500 mA and 11.00V

6.250 mA and 7.50V

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

Given
$${r_d} = 20K\Omega ,\,\,{I_{DSS}}\, = \,10mA,\,\,{V_P} = - 8V$$ GATE ECE 2005 Analog Circuits - FET and MOSFET Question 24 English

Transconductance in milli-Siemens (mS) and voltage gain of the amplifier are respectively.

1.875 mS and 3.41

1.875 mS and -3.41

3.3 mS and -6

3.3 mS and 6

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

The circuit using a BJT with β = 50 and V_BE = 0.7 V is shown in the figure. The base current I_B and collector voltage V_C are respectively GATE ECE 2005 Analog Circuits - Bipolar Junction Transistor Question 43 English

GATE ECE 2005 Analog Circuits - Bipolar Junction Transistor Question 43 English

43 μA and 11.4 Volts

40 μA and 16 Volts

45 μA and 11 Volts

50 μA and 10 Volts

GATE ECE 2005

MCQ (Single Correct Answer)

-0.6

An output of a communication channel is a random variable 'V' with the probability density function as shown in the figure. The mean square value of 'V' is GATE ECE 2005 Communications - Random Signals and Noise Question 54 English

GATE ECE 2005 Communications - Random Signals and Noise Question 54 English

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