GATE ECE 2005 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2005

MCQ (Single Correct Answer)

-0.3

The Boolean expression for the truth table shown is

A	B	C	D
0	0	0	0
0	0	1	0
0	1	0	0
0	1	1	1
1	0	0	0
1	0	1	0
1	1	0	1
1	1	1	0

B(A+C)($$\overline A + \overline C )$$

$$B\left( {A + \overline C } \right)\left( {\overline A + C} \right)$$

$$\overline B $$(A+$$\overline C $$)($$\overline A $$+C)

$$\overline B $$(A+C)(($$\overline A + \overline C )$$

GATE ECE 2005

MCQ (Single Correct Answer)

-0.3

The Boolean function f implemented in the figure using two input multiplexers is GATE ECE 2005 Digital Circuits - Combinational Circuits Question 9 English

GATE ECE 2005 Digital Circuits - Combinational Circuits Question 9 English

$$A\overline B C\, + \,AB\overline C $$

$$ABC\, + \,A\overline B \overline C $$

$$\overline A BC\, + \,\overline A \overline B \overline C $$

$$\overline {AB} C\, + \,\overline A B\overline C $$

GATE ECE 2005

MCQ (Single Correct Answer)

-0.3

The given figure shows a ripple counter using positive edge triggered flip-flops. If the present state of counter is Q₂ Q₁ Q₀ = 011, then its next state ( Q₂ Q₁ Q₀ ) will be GATE ECE 2005 Digital Circuits - Sequential Circuits Question 58 English

GATE ECE 2005 Digital Circuits - Sequential Circuits Question 58 English

010

100

111

101

GATE ECE 2005

MCQ (Single Correct Answer)

-0.3

The present output Q_n of an edge triggered JK flip-flop is logic 0. If J=1, then Q_n+1

can not be determined

will be logic 0

will be logic 1

will race around

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