1
IIT-JEE 2009 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

The $$x$$-$$t$$ graph of a particle undergoing simple harmonic motion is shown in the figure. The acceleration of the particle at $$t=4/3$$ s is

IIT-JEE 2009 Paper 1 Offline Physics - Simple Harmonic Motion Question 5 English

A
$${{\sqrt 3 } \over {32}}{\pi ^2}$$ cm/s$$^2$$
B
$${{ - {\pi ^2}} \over {32}}$$ cm/s$$^2$$
C
$${{ {\pi ^2}} \over {32}}$$ cm/s$$^2$$
D
$$ - {{\sqrt 3 } \over {32}}{\pi ^2}$$ cm/s$$^2$$
2
IIT-JEE 2008 Paper 2 Offline
MCQ (Single Correct Answer)
+4
-1

Column I gives a list of possible set of parameters measured in some experiments. The variations of the parameters in the form of graphs are shown in Column II. Match the set of parameters given in Column I with the graphs given in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 $$\times$$ 4 matrix given in the ORS.

Column I Column II
(A) Potential energy of a simple pendulum (y-axis) as a function of displacement (x) axis (P) IIT-JEE 2008 Paper 2 Offline Physics - Simple Harmonic Motion Question 1 English 1
(B) Displacement (y-axis) as a function of time (x-axis) for a one dimensional motion at zero or constant acceleration when the body is moving along the positive x-direction (Q) IIT-JEE 2008 Paper 2 Offline Physics - Simple Harmonic Motion Question 1 English 2
(C) Range of a projectile (y-axis) as a function of its velocity (x-axis) when projected at a fixed angle (R) IIT-JEE 2008 Paper 2 Offline Physics - Simple Harmonic Motion Question 1 English 3
(D) The square of the time period (y-axis) of a simple pendulum as a function of its length (x-axis) (S) IIT-JEE 2008 Paper 2 Offline Physics - Simple Harmonic Motion Question 1 English 4

A
A$$\to$$(P, S); B$$\to$$(Q, S); C$$\to$$(S); (D)$$\to$$(Q)
B
A$$\to$$(S); B$$\to$$(Q, S); C$$\to$$(S); (D)$$\to$$(Q, S)
C
A$$\to$$(P, S); B$$\to$$(Q); C$$\to$$(S); (D)$$\to$$(Q, S)
D
A$$\to$$(S); B$$\to$$(Q, S); C$$\to$$(S, P); (D)$$\to$$(Q)
3
IIT-JEE 2005 Screening
MCQ (Single Correct Answer)
+2
-0.5
A simple pendulum has time period T1. The point of suspension is now moved upward according to the relation y = Kt2, (K = 1 m/s2) where y is the vertical displacement. The time period now become T2. The ratio of $${{T_1^2} \over {T_2^2}}$$ is (g = 10 m/s2)
A
$${5 \over 6}$$
B
$${6 \over 5}$$
C
1
D
$${4 \over 5}$$
4
IIT-JEE 2001 Screening
MCQ (Single Correct Answer)
+2
-0.5
A particle executes simple harmonic motion between x = - A to x = + A. The time taken for it to go from 0 to $${A \over 2}$$ is T1 and to go from $${A \over 2}$$ to A is T2. Then
A
T1 < T2
B
T1 > T2
C
T1 = T2
D
T1 = 2T2
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