IIT-JEE 1988 | Simple Harmonic Motion Question 27 | Physics

IIT-JEE 1988

MCQ (Single Correct Answer)

-0.25

Two bodies M and N of equal masses are suspended from two separate massless springs of spring constant k₁ and k₂ respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of M to that of N is

$${{{k_1}} \over {{k_2}}}$$

$$\sqrt {{{{k_1}} \over {{k_2}}}} $$

$${{{k_2}} \over {{k_1}}}$$

$$\sqrt {{{{k_2}} \over {{k_1}}}} $$

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