When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx^{2}, it performs simple harmonic motion. The corresponding time period is proportional to $$\sqrt {{m \over k}} $$, as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx^{2} and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = $$\alpha$$x^{4} ($$\alpha$$ > 0) for | x | near the origin and becomes a constant equal to V_{0} for (see figure).

If the total energy of the particle is E, it will perform periodic motion only if

When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx^{2}, it performs simple harmonic motion. The corresponding time period is proportional to $$\sqrt {{m \over k}} $$, as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx^{2} and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = $$\alpha$$x^{4} ($$\alpha$$ > 0) for | x | near the origin and becomes a constant equal to V_{0} for (see figure).

For periodic motion of small amplitude A, the time period T of this particle is proportional to

When a particle of mass m moves on the x-axis in a potential of the form V(x) = kx^{2}, it performs simple harmonic motion. The corresponding time period is proportional to $$\sqrt {{m \over k}} $$, as can be seen easily using dimensional analysis. However, the motion of a particle can be periodic even when its potential energy increases on both sides of x = 0 in a way different from kx^{2} and its total energy is such that the particle does not escape to infinity. Consider a particle of mass m moving on the x-axis. Its potential energy is V(x) = $$\alpha$$x^{4} ($$\alpha$$ > 0) for | x | near the origin and becomes a constant equal to V_{0} for (see figure).

The acceleration of this particle for $$|x| > {X_0}$$ is