1
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The solution of the differential equation $(1+x) \frac{\mathrm{d} y}{\mathrm{~d} x}-x y=1-x$ is

A

$y(1+x)=x+\mathrm{ce}^x$, where c is the constant of integration

B

$\quad y(1+x)=\mathrm{ce}^x$, where c is the constant of integration

C

$y(1-x)=x-\mathrm{ce}^x$, where c is the constant of integration

D

$y(1+x)=x$, where c is the constant of integration

2
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The differential equation representing the family of parabolas having vertex at the origin and axis along the positive Y -axis is

A

$x \frac{\mathrm{~d} y}{\mathrm{~d} x}-2 y=0$

B

$\frac{\mathrm{d} y}{\mathrm{~d} x}+x y=0$

C

$\quad x \frac{\mathrm{~d} y}{\mathrm{~d} x}+y=0$

D

$x^2 \frac{\mathrm{~d} y}{\mathrm{~d} x}+y=0$

3
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The population of towns A and B increase at the rate proportional to their population present at that time. At the end of the year 1984, the population of both the towns was 20,000 . At the end of the year 1989, the population of town A was 25,000 and that of town B was 28,000 . The difference of populations of towns A and B at the end of 1994 was

A

5950

B

8000

C

7950

D

6950

4
MHT CET 2025 26th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of the differential equation $\frac{d y}{d x}=\cot x \cdot \cot y$ is

A

$\cos x=\mathrm{c} \operatorname{cosec} y$, where c is the constant of integration.

B

$\sin x=\mathrm{c} \sec y$, where c is the constant of integration.

C

$\sin x=x \cos y$, where c is the constant of integration.

D

$\cos x=\mathrm{c} \sin y$, where c is the constant of integration.

MHT CET Subjects
EXAM MAP