1
JEE Advanced 2013 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
A solid sphere of radius R and density $$\rho $$ is attached to one end of a mass-less spring of force constant k. The other end of the spring is connected to another solid sphere of radius R and density 3$$\rho $$. The complete arrangement is placed in a liquid of density 2$$\rho $$ and is allowed to reach equilibrium. The correct statement(s) is (are)
A
The net elongation of the spring is $${{4\pi {R^3}\rho g} \over {3k}}$$
B
The net elongation of the spring is $${{8\pi {R^3}\rho g} \over {3k}}$$
C
The light sphere is partially submerged
D
The light sphere is completely submerged
2
IIT-JEE 2012 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2

A person blows into the open end of a long pipe. As a result, a high-pressure pulse of air travels down the pipe. When this pulse reaches the other end of the pipe,

A
a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is open.
B
a low-pressure pulse starts travelling up the pipe, it the other end of the pipe is open.
C
a low-pressure pulse starts travelling up the pipe, if the other end of the pipe is closed.
D
a high-pressure pulse starts travelling up the pipe, if the other end of the pipe is closed.
3
IIT-JEE 2011 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2

A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat Q flows only from left to right through the blocks. Then, in steady-state

IIT-JEE 2011 Paper 1 Offline Physics - Properties of Matter Question 14 English

A
heat flow through A and E slabs are same.
B
heat flow through slab E is maximum.
C
temperature difference across slab E is smallest.
D
heat flow through C = heat flow through B + heat flow through D.
4
IIT-JEE 2011 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2

Two solid spheres A and B of equal volumes but of different densities dA and dB are connected by a string. They are fully immersed in a fluid of density dF. They get arranged into an equilibrium state as shown in the figure with a tension in the string. The arrangement is possible only if

IIT-JEE 2011 Paper 2 Offline Physics - Properties of Matter Question 13 English

A
dA < dF
B
dB > dF
C
dA > dF
D
dA + dB = 2dF
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