1
JEE Advanced 2025 Paper 1 Online
MCQ (Single Correct Answer)
+4
-1
Change Language

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List–I List–II
(P) Passing $\mathrm{H_2S}$ in the presence of $\mathrm{NH_4OH}$ (1) $\mathrm{Cu^{2+}}$
(Q) $\mathrm{(NH_4)_2CO_3}$ in the presence of $\mathrm{NH_4OH}$ (2) $\mathrm{Al^{3+}}$
(R) $\mathrm{NH_4OH}$ in the presence of $\mathrm{NH_4Cl}$ (3) $\mathrm{Mn^{2+}}$
(S) Passing $\mathrm{H_2S}$ in the presence of dilute $\mathrm{HCl}$ (4) $\mathrm{Ba^{2+}}$
(5) $\mathrm{Mg^{2+}}$
A

P → 3; Q → 4; R → 2; S → 1

B

P → 4; Q → 2; R → 3; S → 1

C

P → 3; Q → 4; R → 1; S → 5

D

P → 5; Q → 3; R → 2; S → 4

2
JEE Advanced 2025 Paper 1 Online
MCQ (Single Correct Answer)
+4
-1
Change Language

The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List–I List–II
(P) Stephen reaction (1) $$ \text { Toluene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{CrO}_2 \mathrm{Cl}_2 / \mathrm{CS}_2 \\ \text { (ii) } \mathrm{H}_3 \mathrm{O}^{+} \end{array}} $$
(Q) Sandmeyer reaction (2) $$ \text { Benzoic acid } \xrightarrow{\substack{\text { (i) } \mathrm{PCl}_5 \\ \text { (ii) } \mathrm{NH}_3 \\ \text { (iii) } \mathrm{P}_4 \mathrm{O}_{10}, \Delta}} $$
(R) Hoffmann bromamide degradation reaction (3) $$ \text { Nitrobenzene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{Fe}, \mathrm{HCl} \\ \text { (ii) } \mathrm{HCl}, \mathrm{NaNO}_2 \\ (273-278 \mathrm{~K}), \mathrm{H}_2 \mathrm{O} \end{array}} $$
(S) Cannizzaro reaction (4) $$ \text { Toluene } \xrightarrow{\begin{array}{ll} \text { (i) } \mathrm{Cl}_2 / \mathrm{h\nu}, \mathrm{H}_2 \mathrm{O} \\ \text { (ii) Tollen's reagent } \\ \text { (iii) } \mathrm{SO}_2 \mathrm{Cl}_2 \\ \text { (iv) } \mathrm{NH}_3 \end{array}} $$
(5) $$ \text { Aniline } \xrightarrow{\begin{array}{l} \text { (i) }\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \text { Pyridine } \\ \text { (ii) } \mathrm{HNO}_3, \mathrm{H}_2 \mathrm{SO}_4, 288 \mathrm{~K} \\ \text { (iii) aq. } \mathrm{NaOH} \end{array}} $$
A

P → 2; Q → 4; R → 1; S → 3

B

P → 2; Q → 3; R → 4; S → 1

C

P → 5; Q → 3; R → 4; S → 2

D

P → 5; Q → 4; R → 2; S → 1

3
JEE Advanced 2025 Paper 1 Online
MCQ (Single Correct Answer)
+4
-1
Change Language

Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.

List–I List–II
(P) JEE Advanced 2025 Paper 1 Online Chemistry - Practical Organic Chemistry Question 1 English 1 (1) Reaction with phenyl diazonium salt gives yellow dye.
(Q) JEE Advanced 2025 Paper 1 Online Chemistry - Practical Organic Chemistry Question 1 English 2 (2) Reaction with ninhydrin gives purple color and it also reacts with FeCl3 to give violet color.
(R) JEE Advanced 2025 Paper 1 Online Chemistry - Practical Organic Chemistry Question 1 English 3 (3) Reaction with glucose will give corresponding hydrazone.
(S) JEE Advanced 2025 Paper 1 Online Chemistry - Practical Organic Chemistry Question 1 English 4 (4) Lassiagne extract of the compound treated with dilute HCl followed by addition of aqueous $\mathrm{FeCl}_3$ gives blood red color.
(5) After complete hydrolysis, it will give ninhydrin test and it DOES NOT give positive phthalein dye test.
A

P → 1; Q → 5; R → 4; S → 2

B

P → 2; Q → 5; R → 1; S → 3

C

P → 5; Q → 2; R → 1; S → 4

D

P → 2; Q → 1; R → 5; S → 3

4
JEE Advanced 2025 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Let $\mathbb{R}$ denote the set of all real numbers. Let $a_i, b_i \in \mathbb{R}$ for $i \in \{1, 2, 3\}$.

Define the functions $f: \mathbb{R} \to \mathbb{R}$, $g: \mathbb{R} \to \mathbb{R}$, and $h: \mathbb{R} \to \mathbb{R}$ by

$f(x) = a_1 + 10x + a_2 x^2 + a_3 x^3 + x^4$

$g(x) = b_1 + 3x + b_2 x^2 + b_3 x^3 + x^4$

$h(x) = f(x + 1) - g(x + 2)$

If $f(x) \neq g(x)$ for every $x \in \mathbb{R}$, then the coefficient of $x^3$ in $h(x)$ is

A

8

B

2

C

-4

D

-6

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