JEE Advanced 2025 Paper 1 Online | JEE Advanced Year Wise Previous Years Questions

JEE Advanced 2025 Paper 1 Online

Numerical

-0

The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ______.

JEE Advanced 2025 Paper 1 Online Chemistry - Alcohols, Phenols and Ethers Question 1 English

Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80

Your input ____

JEE Advanced 2025 Paper 1 Online

MCQ (Single Correct Answer)

-1

The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List–I	List–II
(P) Passing $\mathrm{H_2S}$ in the presence of $\mathrm{NH_4OH}$	(1) $\mathrm{Cu^{2+}}$
(Q) $\mathrm{(NH_4)_2CO_3}$ in the presence of $\mathrm{NH_4OH}$	(2) $\mathrm{Al^{3+}}$
(R) $\mathrm{NH_4OH}$ in the presence of $\mathrm{NH_4Cl}$	(3) $\mathrm{Mn^{2+}}$
(S) Passing $\mathrm{H_2S}$ in the presence of dilute $\mathrm{HCl}$	(4) $\mathrm{Ba^{2+}}$
	(5) $\mathrm{Mg^{2+}}$

P → 3; Q → 4; R → 2; S → 1

P → 4; Q → 2; R → 3; S → 1

P → 3; Q → 4; R → 1; S → 5

P → 5; Q → 3; R → 2; S → 4

JEE Advanced 2025 Paper 1 Online

MCQ (Single Correct Answer)

-1

The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List–I	List–II
(P) Stephen reaction	(1) $$ \text { Toluene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{CrO}_2 \mathrm{Cl}_2 / \mathrm{CS}_2 \\ \text { (ii) } \mathrm{H}_3 \mathrm{O}^{+} \end{array}} $$
(Q) Sandmeyer reaction	(2) $$ \text { Benzoic acid } \xrightarrow{\substack{\text { (i) } \mathrm{PCl}_5 \\ \text { (ii) } \mathrm{NH}_3 \\ \text { (iii) } \mathrm{P}_4 \mathrm{O}_{10}, \Delta}} $$
(R) Hoffmann bromamide degradation reaction	(3) $$ \text { Nitrobenzene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{Fe}, \mathrm{HCl} \\ \text { (ii) } \mathrm{HCl}, \mathrm{NaNO}_2 \\ (273-278 \mathrm{~K}), \mathrm{H}_2 \mathrm{O} \end{array}} $$
(S) Cannizzaro reaction	(4) $$ \text { Toluene } \xrightarrow{\begin{array}{ll} \text { (i) } \mathrm{Cl}_2 / \mathrm{h\nu}, \mathrm{H}_2 \mathrm{O} \\ \text { (ii) Tollen's reagent } \\ \text { (iii) } \mathrm{SO}_2 \mathrm{Cl}_2 \\ \text { (iv) } \mathrm{NH}_3 \end{array}} $$
	(5) $$ \text { Aniline } \xrightarrow{\begin{array}{l} \text { (i) }\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \text { Pyridine } \\ \text { (ii) } \mathrm{HNO}_3, \mathrm{H}_2 \mathrm{SO}_4, 288 \mathrm{~K} \\ \text { (iii) aq. } \mathrm{NaOH} \end{array}} $$

P → 2; Q → 4; R → 1; S → 3

P → 2; Q → 3; R → 4; S → 1

P → 5; Q → 3; R → 4; S → 2

P → 5; Q → 4; R → 2; S → 1

JEE Advanced 2025 Paper 1 Online

MCQ (Single Correct Answer)

-1

Match the compounds in List-I with the appropriate observations in List-II and choose the correct option.

List–I	List–II
(P)	(1) Reaction with phenyl diazonium salt gives yellow dye.
(Q)	(2) Reaction with ninhydrin gives purple color and it also reacts with FeCl₃ to give violet color.
(R)	(3) Reaction with glucose will give corresponding hydrazone.
(S)	(4) Lassiagne extract of the compound treated with dilute HCl followed by addition of aqueous $\mathrm{FeCl}_3$ gives blood red color.
	(5) After complete hydrolysis, it will give ninhydrin test and it DOES NOT give positive phthalein dye test.