JEE Advanced 2025 Paper 1 Online | JEE Advanced Year Wise Previous Years Questions

JEE Advanced 2025 Paper 1 Online

Numerical

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The monomer (X) involved in the synthesis of Nylon 6,6 gives positive carbylamine test. If 10 moles of X are analyzed using Dumas method, the amount (in grams) of nitrogen gas evolved is ______.

Use: Atomic mass of N (in amu) = 14

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JEE Advanced 2025 Paper 1 Online

Numerical

-0

The reaction sequence given below is carried out with 16 moles of X. The yield of the major product in each step is given below the product in parentheses. The amount (in grams) of S produced is ______.

JEE Advanced 2025 Paper 1 Online Chemistry - Alcohols, Phenols and Ethers Question 1 English

Use: Atomic mass (in amu): H = 1, C = 12, O = 16, Br = 80

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JEE Advanced 2025 Paper 1 Online

MCQ (Single Correct Answer)

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The correct match of the group reagents in List-I for precipitating the metal ion given in List-II from solutions, is

List–I	List–II
(P) Passing $\mathrm{H_2S}$ in the presence of $\mathrm{NH_4OH}$	(1) $\mathrm{Cu^{2+}}$
(Q) $\mathrm{(NH_4)_2CO_3}$ in the presence of $\mathrm{NH_4OH}$	(2) $\mathrm{Al^{3+}}$
(R) $\mathrm{NH_4OH}$ in the presence of $\mathrm{NH_4Cl}$	(3) $\mathrm{Mn^{2+}}$
(S) Passing $\mathrm{H_2S}$ in the presence of dilute $\mathrm{HCl}$	(4) $\mathrm{Ba^{2+}}$
	(5) $\mathrm{Mg^{2+}}$

P → 3; Q → 4; R → 2; S → 1

P → 4; Q → 2; R → 3; S → 1

P → 3; Q → 4; R → 1; S → 5

P → 5; Q → 3; R → 2; S → 4

JEE Advanced 2025 Paper 1 Online

MCQ (Single Correct Answer)

-1

The major products obtained from the reactions in List-II are the reactants for the named reactions mentioned in List-I. Match each entry in List-I with the appropriate entry in List-II and choose the correct option.

List–I	List–II
(P) Stephen reaction	(1) $$ \text { Toluene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{CrO}_2 \mathrm{Cl}_2 / \mathrm{CS}_2 \\ \text { (ii) } \mathrm{H}_3 \mathrm{O}^{+} \end{array}} $$
(Q) Sandmeyer reaction	(2) $$ \text { Benzoic acid } \xrightarrow{\substack{\text { (i) } \mathrm{PCl}_5 \\ \text { (ii) } \mathrm{NH}_3 \\ \text { (iii) } \mathrm{P}_4 \mathrm{O}_{10}, \Delta}} $$
(R) Hoffmann bromamide degradation reaction	(3) $$ \text { Nitrobenzene } \xrightarrow{\begin{array}{l} \text { (i) } \mathrm{Fe}, \mathrm{HCl} \\ \text { (ii) } \mathrm{HCl}, \mathrm{NaNO}_2 \\ (273-278 \mathrm{~K}), \mathrm{H}_2 \mathrm{O} \end{array}} $$
(S) Cannizzaro reaction	(4) $$ \text { Toluene } \xrightarrow{\begin{array}{ll} \text { (i) } \mathrm{Cl}_2 / \mathrm{h\nu}, \mathrm{H}_2 \mathrm{O} \\ \text { (ii) Tollen's reagent } \\ \text { (iii) } \mathrm{SO}_2 \mathrm{Cl}_2 \\ \text { (iv) } \mathrm{NH}_3 \end{array}} $$
	(5) $$ \text { Aniline } \xrightarrow{\begin{array}{l} \text { (i) }\left(\mathrm{CH}_3 \mathrm{CO}\right)_2 \mathrm{O}, \text { Pyridine } \\ \text { (ii) } \mathrm{HNO}_3, \mathrm{H}_2 \mathrm{SO}_4, 288 \mathrm{~K} \\ \text { (iii) aq. } \mathrm{NaOH} \end{array}} $$