JEE Advanced 2022 Paper 1 Online | JEE Advanced Year Wise Previous Years Questions

JEE Advanced 2022 Paper 1 Online

MCQ (Single Correct Answer)

-1

Match the rate expressions in LIST-I for the decomposition of $X$ with the corresponding profiles provided in LIST-II. $X_{\mathrm{s}}$ and $\mathrm{k}$ are constants having appropriate units.

List-I	List-II
(I) rate $=\frac{\mathrm{k}[\mathrm{X}]}{\mathrm{X}_{\mathrm{s}}+[\mathrm{X}]}$ under all possible initial concentrations of $\mathrm{X}$	(P)
(II) rate $=\frac{k[X]}{X_{s}+[X]}$ where initial concentrations of $X$ are much less than $X_{s}$	(Q)
(III) rate $=\frac{k[X]}{X_{s}+[X]}$ where initial concentrations of $\mathrm{X}$ are much higher than $X_{s}$	(R)
(IV) rate $=\frac{k[X]^{2}}{X_{s}+[X]}$ where initial concentration of $X$ is much higher than $\mathrm{X}_{\mathrm{s}}$	(S)
	(T)

$\mathrm{I} \rightarrow \mathrm{P}$; II $\rightarrow$ Q; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{T}$

$\mathrm{I} \rightarrow \mathrm{R}$; II $\rightarrow \mathrm{S}$; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{T}$

$\mathrm{I} \rightarrow \mathrm{P}$; II $\rightarrow$ Q; III $\rightarrow$ Q; IV $\rightarrow$ R

$\mathrm{I} \rightarrow \mathrm{R}$; II $\rightarrow \mathrm{S}$; III $\rightarrow$ Q; IV $\rightarrow \mathrm{R}$

JEE Advanced 2022 Paper 1 Online

MCQ (Single Correct Answer)

-1

LIST-I contains compounds and LIST-II contains reactions

List-I	List-II
(I) $\mathrm{H}_{2} \mathrm{O}_{2}$	(P) $\mathrm{Mg}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$
(II) $\mathrm{Mg}(\mathrm{OH})_{2}$	(Q) $\mathrm{BaO}_{2}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow$
(III) $\mathrm{BaCl}_{2}$	(R) $\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{MgCl}_{2} \rightarrow$
(IV) $\mathrm{CaCO}_{3}$	(S) $\mathrm{BaO}_{2}+\mathrm{HCl} \rightarrow$
	(T) $\mathrm{Ca}\left(\mathrm{HCO}_{3}\right)_{2}+\mathrm{Ca}(\mathrm{OH})_{2} \rightarrow$

Match each compound in LIST-I with its formation reaction(s) in LIST-II, and choose the correct option

I $\rightarrow$ Q; II $\rightarrow$ P; III $\rightarrow$ S; IV $\rightarrow$ R

I $\rightarrow$ T; II $\rightarrow$ P; III $\rightarrow$ Q; IV $\rightarrow$ R

I $\rightarrow$ T; II $\rightarrow$ R; III $\rightarrow$ Q; IV $\rightarrow$ P

I $\rightarrow$ Q; II $\rightarrow$ R; III $\rightarrow$ S; IV $\rightarrow$ P

JEE Advanced 2022 Paper 1 Online

MCQ (Single Correct Answer)

-1

LIST-I contains metal species and LIST-II contains their properties.

List-I	List-II
(I) $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{4-}$	(P) $t_{2 \mathrm{g}}$ orbitals contain 4 electrons
(II) $\left[\mathrm{RuCl}_{6}\right]^{2-}$	(Q) $\mu$ (spin-only $)=4.9 \mathrm{BM}$
(III) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$	(R) low spin complex ion
(IV) $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$	(S) metal ion in $4+$ oxidation state
	(T) $d^{4}$ species

[Given: Atomic number of $\mathrm{Cr}=24, \mathrm{Ru}=44, \mathrm{Fe}=26$ ]

Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option

I $\rightarrow$ R, T; II $\rightarrow$ P, S; III $\rightarrow$ Q, T; IV $\rightarrow$ P, Q

I $\rightarrow$ R, S; II $\rightarrow$ P, T; III $\rightarrow$ P, Q; IV $\rightarrow$ Q, T

I $\rightarrow$ P, R; II $\rightarrow$ R, S; III $\rightarrow$ R, T; IV $\rightarrow$ P, T

I $\rightarrow$ Q, T; II $\rightarrow$ S, T; III $\rightarrow$ P, T; IV $\rightarrow$ Q, R

JEE Advanced 2022 Paper 1 Online

MCQ (Single Correct Answer)

-1

Match the compounds in LIST-I with the observations in LIST-II, and choose the correct option.

List-I	List-II
(I) Aniline	(P) Sodium fusion extract of the compound on boiling with $\mathrm{FeSO}_{4}$, followed by acidification with conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$, gives Prussian blue color.
(II) $o$-Cresol	(Q) Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
(III) Cysteine	(R) Addition of the compound to a saturated solution of $\mathrm{NaHCO}_{3}$ results in effervescence.
(IV) Caprolactam	(S) The compound reacts with bromine water to give a white precipitate.
	(T) Treating the compound with neutral $\mathrm{FeCl}_{3}$ solution produces violet color.

$\mathrm{I} \rightarrow \mathrm{P}, \mathrm{Q}$; II $\rightarrow \mathrm{S} ; \mathrm{III} \rightarrow \mathrm{Q}, \mathrm{R}$; IV $\rightarrow \mathrm{P}$

$\mathrm{I} \rightarrow \mathrm{P}$; II $\rightarrow \mathrm{R}$, $\mathrm{S}$; III $\rightarrow \mathrm{R}$; $\mathrm{IV} \rightarrow \mathrm{Q}, \mathrm{S}$

$\mathrm{I} \rightarrow \mathrm{Q}, \mathrm{S}$; II $\rightarrow \mathrm{P}, \mathrm{T}$; III $\rightarrow \mathrm{P}$; IV $\rightarrow \mathrm{S}$

$\mathrm{I} \rightarrow \mathrm{P}$, S; II $\rightarrow \mathrm{T}$; III $\rightarrow \mathrm{Q}, \mathrm{R}$; $\mathrm{IV} \rightarrow \mathrm{P}$

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