1
JEE Advanced 2021 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Precipitate X is
A
Fe4[Fe(CN)6]3
B
Fe[Fe(CN)6]
C
K2Fe[Fe(CN)6]
D
KFe[Fe(CN)6]
2
JEE Advanced 2021 Paper 2 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
The reaction of K3[Fe(CN)6] with freshly prepared FeSO4 solution produces a dark blue precipitate called Turnbull's blue. Reaction of K4[Fe(CN)6] with the FeSO4 solution in complete absence of air produces a white precipitate X, which turns blue in air. Mixing the FeSO4 solution with NaNO3, followed by a slow addition of concentrated H2SO4 through the side of the test tube produces a brown ring.
Among the following, the brown ring is due to the formation of
A
[Fe(NO)2](SO4)2]2$$-$$
B
[Fe(NO)2](H2O)4]3+
C
[Fe(NO)4](SO4)2]
D
[Fe(NO)(H2O)5]2+
3
JEE Advanced 2021 Paper 2 Online
Numerical
+4
-0
Change Language
One mole of an ideal gas at 900 K, undergoes two reversible processes, I followed by II, as shown below. If the work done by the gas in the two processes are same, the value of $$\ln {{{V_3}} \over {{V_2}}}$$ is _________.

JEE Advanced 2021 Paper 2 Online Chemistry - Thermodynamics Question 15 English
(U : internal energy, S : entropy, p : pressure, V : volume, R : gas constant)

(Given : molar heat capacity at constant volume, CV,m of the gas is $${5 \over 2}$$R)
Your input ____
4
JEE Advanced 2021 Paper 2 Online
Numerical
+4
-0
Change Language
Consider a helium (He) atom that absorbs a photon of wavelength 330 nm. The change in the velocity (in cm s$$-$$1) of He atom after the photon absorption is __________.

(Assume : Momentum is conserved when photon is absorbed.

Use : Planck constant = 6.6 $$\times$$ 10$$-$$34 J s, Avogadro number = 6 $$\times$$ 1023 mol$$-$$1, Molar mass of He = 4 g mol$$-$$1)
Your input ____
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