Reaction of x g of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with y g of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).

(Use Molar masses (in g mol^$$-$$1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively).

The value of y is _________.

A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO₄ solution to reach the end point. Number of moles of Fe²⁺ present in 250 mL solution is x $$\times$$ 10^$$-$$2 (consider complete dissolution of FeCl₂). The amount of iron present in the sample is y% by weight.

(Assume : KMnO₄ reacts only with Fe²⁺ in the solution

Use : Molar mass of iron as 56 g mol^$$-$$1)

The value of x is ______.

A sample (5.6 g) containing iron is completely dissolved in cold dilute HCl to prepare a 250 mL of solution. Titration of 25.0 mL of this solution requires 12.5 mL of 0.03 M KMnO₄ solution to reach the end point. Number of moles of Fe²⁺ present in 250 mL solution is x $$\times$$ 10^$$-$$2 (consider complete dissolution of FeCl₂). The amount of iron present in the sample is y% by weight.

(Assume : KMnO₄ reacts only with Fe²⁺ in the solution

Use : Molar mass of iron as 56 g mol^$$-$$1)

The value of y is ______.

The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below :

Correct match of the C-H bonds (shown in bold) in Column J with their BDE in Column K is

Column J Molecule	Column K BDE (kcal $$mo{l^{ - 1}}$$)
(P) H-CH($$C{H_3}$$)$$_2$$	(i) 132
(Q) H-CH$$_2$$Ph	(ii) 110
(R) H-CH=CH$$_2$$	(iii) 95
(S) H-C $$ \equiv $$ CH	(iv) 88