1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
The reaction of compound $$P$$ with $$C{H_3}MgBr$$ (excess) in $${\left( {{C_2}{H_5}} \right)_2}O$$ followed by addition of $${H_2}O$$ gives $$Q.$$ The compound $$Q$$ on treatment with $${H_2}S{O_4}$$ at $${0^ \circ }C$$ gives $$R.$$ The reaction of $$R$$ with $$C{H_3}COCl$$ in the presence of anhydrous $$AlC{l_3}$$ in $$C{H_2}C{l_2}$$ followed by treatment with $${H_2}O$$ producess compound $$S.$$ [$$Et$$ in compound $$P$$ is ethyl group]

JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 53 English Comprehension
The product $$S$$ is
A
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 53 English Option 1
B
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 53 English Option 2
C
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 53 English Option 3
D
JEE Advanced 2017 Paper 2 Offline Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 53 English Option 4
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Upon heating $$KCl{O_3}$$ in the presence of catalytic amount of $$Mn{O_2},$$ a gas $$W$$ is formed. Excess amount of $$W$$ reacts with white phosphorous to give $$X.$$ The reaction of $$X$$ with pure $$HN{O_3}$$ gives $$Y$$ and $$Z.$$
$$Y$$ and $$Z$$ are, respectively
A
$${N_2}{O_3}$$ and $${H_3}P{O_4}$$
B
$${N_2}{O_5}$$ and $$HP{O_3}$$
C
$${N_2}{O_4}$$ and $$HP{O_3}$$
D
$${N_2}{O_4}$$ and $${H_3}P{O_3}$$
3
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
If f : R $$ \to $$ R is a twice differentiable function such that f"(x) > 0 for all x$$ \in $$R, and $$f\left( {{1 \over 2}} \right) = {1 \over 2}$$, f(1) = 1, then
A
f'(1) $$ \le $$ 0
B
f'(1) > 1
C
0 < f'(1) $$ \le $$ $${1 \over 2}$$
D
$${1 \over 2}$$ < f'(1) $$ \le $$ 1
4
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
If y = y(x) satisfies the differential equation

$${8\sqrt x \left( {\sqrt {9 + \sqrt x } } \right)dy = {{\left( {\sqrt {4 + \sqrt {9 + \sqrt x } } } \right)}^{ - 1}}}$$

dx, x > 0 and y(0) = $$\sqrt 7 $$, then y(256) =
A
16
B
3
C
9
D
80
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