1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
Consider a simple RC circuit as shown in Figure 1.

Process 1 : In the circuit the switch S is closed at t = 0 and the capacitor is fully charged to voltage V0 (i.e. charging continues for time T >> RC). In the process some dissipation (ED) occurs across the resistance R. The amount of energy finally stored in the fully charged capacitor is EC.

Process 2 : In a different process the voltage is first set to $${{{V_0}} \over 3}$$ and maintained for a charging time T >> RC. Then, the voltage is raised to $${{2{V_0}} \over 3}$$ without discharging the capacitor and again maintained for a time T >> RC. The process is repeated one more time by raising the voltage to V0 and the capacitor is charged to the same final voltage V0 as in Process 1.

These two processes are depicted in Figure 2.
JEE Advanced 2017 Paper 2 Offline Physics - Alternating Current Question 10 English Comprehension
In Process 1, the energy stored in the capacitor EC and heat dissipated across resistance ED are related by
A
EC = ED ln2
B
EC = ED
C
EC = 2ED
D
EC = $${1 \over 2}$$ED
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
Consider a simple RC circuit as shown in Figure 1.

Process 1 : In the circuit the switch S is closed at t = 0 and the capacitor is fully charged to voltage V0 (i.e. charging continues for time T >> RC). In the process some dissipation (ED) occurs across the resistance R. The amount of energy finally stored in the fully charged capacitor is EC.

Process 2 : In a different process the voltage is first set to $${{{V_0}} \over 3}$$ and maintained for a charging time T >> RC. Then, the voltage is raised to $${{2{V_0}} \over 3}$$ without discharging the capacitor and again maintained for a time T >> RC. The process is repeated one more time by raising the voltage to V0 and the capacitor is charged to the same final voltage V0 as in Process 1.

These two processes are depicted in Figure 2.

JEE Advanced 2017 Paper 2 Offline Physics - Alternating Current Question 9 English Comprehension
In Process 2, total energy dissipated across the resistance ED is
A
$${E_D} = {1 \over 3}\left( {{1 \over 2}CV_0^2} \right)$$
B
$${E_D} = 3\left( {{1 \over 2}CV_0^2} \right)$$
C
$${E_D} = 3CV_0^2$$
D
$${E_D} = {1 \over 2}CV_0^2$$
3
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
One twirls a circular ring (of mass M and radius R) near the tip of one's finger as shown in Figure 1. In the process the finger never loses contact with the inner rim of the ring. The finger traces out the surface of a cone, shown by the dotted line. The radius of the path traced out by the point where the ring and the finger is in contact is r. The finger rotates with an angular velocity $$\omega$$0. The rotating ring rolls without slipping on the outside of a smaller circle described by the point where the ring and the finger is in contact (Figure 2). The coefficient of friction between the ring and the finger is $$\mu$$ and the acceleration due to gravity is g.

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 25 English Comprehension
The total kinetic energy of the ring is
A
$$M\omega _0^2{(R - r)^2}$$
B
$${1 \over 2}M\omega _0^2{(R - r)^2}$$
C
$$M\omega _0^2{R^2}$$
D
$${1 \over 2}M\omega _0^2[{(R - r)^2} + {R^2}]$$
4
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0
One twirls a circular ring (of mass M and radius R) near the tip of one's finger as shown in Figure 1. In the process the finger never loses contact with the inner rim of the ring. The finger traces out the surface of a cone, shown by the dotted line. The radius of the path traced out by the point where the ring and the finger is in contact is r. The finger rotates with an angular velocity $$\omega$$0. The rotating ring rolls without slipping on the outside of a smaller circle described by the point where the ring and the finger is in contact (Figure 2). The coefficient of friction between the ring and the finger is $$\mu$$ and the acceleration due to gravity is g.

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 26 English Comprehension
The minimum value of $$\omega$$0 below which the ring will drop down is
A
$$\sqrt {{g \over {2\mu (R - r)}}} $$
B
$$\sqrt {{{3g} \over {2\mu (R - r)}}} $$
C
$$\sqrt {{g \over {\mu (R - r)}}} $$
D
$$\sqrt {{{2g} \over {\mu (R - r)}}} $$
JEE Advanced Papers
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12