1
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
A symmetric star shaped conducting wire loop is carrying a steady state current $${\rm I}$$ as shown in the figure. The distance between the diametrically opposite vertices of the star is $$4a.$$ The magnitude of the magnetic field at the center of the loop is

JEE Advanced 2017 Paper 2 Offline Physics - Magnetism Question 37 English
A
$${{{\mu _0}1} \over {4\pi a}}6\left[ {\sqrt 3 - 1} \right]$$
B
$${{{\mu _0}1} \over {4\pi a}}6\left[ {\sqrt 3 + 1} \right]$$
C
$${{{\mu _0}1} \over {4\pi a}}3\left[ {\sqrt 3 - 1} \right]$$
D
$${{{\mu _0}1} \over {4\pi a}}3\left[ {2 - \sqrt 3 } \right]$$
2
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Consider regular polygons with number of sides $$n=3,4,5....$$ as shown in the figure. The center of mass of all the polygons is at height $$h$$ from the ground. They roll on a horizontal surface about the leading vertex without slipping and sliding as depicted. The maximum increase in height of the locus of the center of mass for each polygon is $$\Delta $$. Then $$\Delta $$ depends on $$n$$ and $$h$$ as

JEE Advanced 2017 Paper 2 Offline Physics - Rotational Motion Question 38 English
A
$$\Delta = h{\sin ^2}\left( {{\pi \over n}} \right)$$
B
$$\Delta = h\left( {{1 \over {\cos \left( {{\pi \over n}} \right)}} - 1} \right)$$
C
$$\Delta = h\sin \left( {{{2\pi } \over n}} \right)$$
D
$$\Delta = h\,{\tan ^2}\left( {{\pi \over {2n}}} \right)$$
3
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Three vectors $$\overrightarrow P ,\overrightarrow Q $$ and $$\overrightarrow R $$ are shown in the figure. Let $$S$$ be any point on the vector $$\overrightarrow R .$$ The distance between the points $$P$$ and $$S$$ is $$b\left| {\overrightarrow R } \right|.$$ The general relation among vectors $$\overrightarrow P ,\overrightarrow Q $$ and $$\overrightarrow S $$ is

JEE Advanced 2017 Paper 2 Offline Physics - Motion Question 5 English
A
$$\overrightarrow S = \left( {1 - b} \right)\overrightarrow P + b\overrightarrow Q $$
B
$$\overrightarrow S = \left( {b - 1} \right)\overrightarrow P + b\overrightarrow Q $$
C
$$\overrightarrow S = \left( {1 - {b^2}} \right)\overrightarrow P + b\overrightarrow Q $$
D
$$\overrightarrow S = \left( {1 - b} \right)\overrightarrow P + {b^2}\overrightarrow Q $$
4
JEE Advanced 2017 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
A rocket is launched normal to the surface of the Earth, away from the sun, along the line joining the Sun and the Earth. The Sun is $$3 \times 10{}^5$$ times heavier than the earth and is at a distance $$2.5 \times {10^4}$$ times larger than the radius of the Earth. The escape velocity from Earth's gravitational field is $${V_c} = 11.2km\,{s^{ - 1}}.$$. The minimum initial velocity $$\left( {{v_s}} \right)$$ required for the rocket to be able to leave the sun-earth system is closest to (Ignore the the rotation and revoluation of the earth and the presence of any other planet) $${v_s} = 72km{s^{ - 1}}$$
A
$${v_s} = 22\,km\,{s^{ - 1}}$$
B
$${v_s} = 42\,km\,{s^{ - 1}}$$
C
$${v_s} = 62km\,{s^{ - 1}}$$
D
$${v_s} = 72km{s^{ - 1}}$$
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