1
IIT-JEE 2010 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
When liquid medicine of density $$\rho $$ is to be put in the eye, it is done with the help of a dropper. As the bulb on the top of the dropper is pressed, a drop forms at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy. To determine the size, we calculate the net vertical force due to the surface tension T when the radius of the drop is R. When the force becomes smaller than the weight of the drop, the drop gets detached from the dropper.

After the drop detaches, its surface energy is

A
1.4 $$ \times $$ 10−6 J
B
2.7 $$ \times $$ 10−6 J
C
5.4 $$ \times $$ 10−6 J
D
8.1 $$ \times $$ 10−6 J
2
IIT-JEE 2010 Paper 2 Offline
Numerical
+3
-0
A diatomic ideal gas is compressed adiabatically $${1 \over {32}}$$ of its initial volume. If the initial temperature of the gas is Ti (in Kelvin) and the final temperature is a Ti, the value of $$a$$ is
Your input ____
3
IIT-JEE 2010 Paper 2 Offline
MCQ (Single Correct Answer)
+5
-1.25
A hollow pipe of length 0.8 m is closed at one end. At its open end a 0.5 m long uniform string is vibrating in its second harmonic and it resonates with the fundamental frequency of the pipe. If the tension in the wire is 50 N and the speed of sound is 320 ms−1, the mass of the string is
A
5 grams
B
10 grams
C
20 grams
D
40 grams
4
IIT-JEE 2010 Paper 2 Offline
MCQ (Single Correct Answer)
+2
-0.5
A tiny spherical oil drop carrying a net charge $$q$$ is balanced in still air with a vertical uniform electric field of strength $${{81\pi } \over 7} \times {10^5}\,\,V{m^{ - 1}}.$$ When the field is switched off, the drop is observed to fall with terminal velocity $$2 \times {10^{ - 3}}\,\,m{s^{ - 1}}.$$ Given $$g = 9.8\,m\,{s^{ - 2}},$$ viscosity of the air $$ = 1.8 \times {10^{ - 5}}\,\,Ns\,{m^{ - 2}}$$ and the density of coil $$=900$$ $$kg$$ $${m^{ - 3}},$$ the magnitude of $$q$$ is
A
$$1.6 \times {10^{ - 19}}C$$
B
$$3.2 \times {10^{ - 19}}C$$
C
$$4.8 \times {10^{ - 19}}C$$
D
$$8.0 \times {10^{ - 19}}C$$
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