1
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
Group I gives two possible choices for the impedance Z in the diagram. The circuit elements in Z satisfy the condition $${R_2}{C_2} > {R_1}{C_{1.}}$$ The transfer $${\textstyle{{{V_0}} \over {{V_1}}}}$$ function represents a kind of controller. Match the impedances in Group I with the types of controllers in Group II. GATE ECE 2008 Control Systems - Compensators Question 12 English 1 Group - I GATE ECE 2008 Control Systems - Compensators Question 12 English 2

Group - II
1. PID controller
2. Lead compensator
3. Lag compensator

A
Q - 1, R - 2
B
Q - 1, R - 3
C
Q - 2, R - 3
D
Q - 3, R - 2
2
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
The impulse response h(t) of a linear time invariant system is given by h(t) = $${e^{ - 2t}}u(t),$$ where u(t) denotes the unit step function.

The output of this system to the sinusoidal input x(t) = 2cos(t) for all time 't' is

A
$$0$$
B
$${2^{ - 0.25}}\cos \left( {2t - 0.125\pi } \right)$$
C
$${2^{ - 0.5}}\cos \left( {2t - 0.125\pi } \right)$$
D
$${2^{ - 0.5}}\cos \left( {2t - 0.25\pi } \right)$$
3
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
The logic function implemented by the following circuit at the terminal OUT is GATE ECE 2008 Digital Circuits - Logic Families Question 3 English
A
P NOR Q
B
P NAND Q
C
P OR Q
D
P AND Q
4
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
In the following circuit, the comparator output is logic “I” if V1 > V2 and is logic “0” otherwise. The D/A conversion is done as per the relation $$${V_{DAC}} = \sum\limits_{n = 0}^3 {{2^{n - 1}}{b_n}\,\,} Volts,$$$ where b3(MSB), b2, b1 and b0 (LSB) are the counter outputs.

The counter starts from the clear state.

GATE ECE 2008 Digital Circuits - Analog to Digital and Digital to Analog Converters Question 8 English

The magnitude of the error between VDAC and Vin at steady state in volts is

A
0.2
B
0.3
C
0.5
D
1