1
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
Group I gives two possible choices for the impedance Z in the diagram. The circuit elements in Z satisfy the condition $${R_2}{C_2} > {R_1}{C_{1.}}$$ The transfer $${\textstyle{{{V_0}} \over {{V_1}}}}$$ function represents a kind of controller. Match the impedances in Group I with the types of controllers in Group II. GATE ECE 2008 Control Systems - Compensators Question 9 English 1 Group - I GATE ECE 2008 Control Systems - Compensators Question 9 English 2

Group - II
1. PID controller
2. Lead compensator
3. Lag compensator

A
Q - 1, R - 2
B
Q - 1, R - 3
C
Q - 2, R - 3
D
Q - 3, R - 2
2
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
A signal flow graph of a system is given below. GATE ECE 2008 Control Systems - State Space Analysis Question 25 English

The set of equations that correspond to this signal flow graph is

A
$${d \over {dt}}\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] = \left[ {\matrix{ \beta & { - \gamma } & 0 \cr \gamma & \alpha & 0 \cr { - \alpha } & { - \beta } & 0 \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] + \left[ {\matrix{ 1 & 0 \cr 0 & 0 \cr 0 & 1 \cr } } \right]\left( {\matrix{ {{u_1}} \cr {{u_2}} \cr } } \right)$$
B
$${d \over {dt}}\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] = \left[ {\matrix{ 0 & \alpha & \gamma \cr 0 & { - \alpha } & { - \gamma } \cr 0 & \beta & { - \beta } \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] + \left[ {\matrix{ 0 & 0 \cr 0 & 1 \cr 1 & 0 \cr } } \right]\left( {\matrix{ {{u_1}} \cr {{u_2}} \cr } } \right)$$
C
$${d \over {dt}}\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] = \left[ {\matrix{ { - \alpha } & \beta & 0 \cr { - \beta } & { - \gamma } & 0 \cr \alpha & \gamma & 0 \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] + \left[ {\matrix{ 1 & 0 \cr 0 & 1 \cr 0 & 0 \cr } } \right]\left( {\matrix{ {{u_1}} \cr {{u_2}} \cr } } \right)$$
D
$${d \over {dt}}\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] = \left[ {\matrix{ { - \gamma } & 0 & \beta \cr \gamma & 0 & \alpha \cr { - \beta } & 0 & { - \alpha } \cr } } \right]\left[ {\matrix{ {{x_1}} \cr {{x_2}} \cr {{x_3}} \cr } } \right] + \left[ {\matrix{ 0 & 1 \cr 0 & 0 \cr 1 & 0 \cr } } \right]\left( {\matrix{ {{u_1}} \cr {{u_2}} \cr } } \right)$$
3
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
For the circuit shown in the following figure $${I_0}$$ - $${I_3}$$ are inputs to the 4:1 multiplexer R(MSB) and S are control bits. tHE OUTPUT Zcan be represented by GATE ECE 2008 Digital Circuits - Combinational Circuits Question 27 English
A
PQ+P$$\overline {Q\,} S + \,\overline {Q\,} \overline R \,\overline S $$
B
$$P\,\overline {Q\,} + PQ\,\overline R \, + \,\overline R \,\overline {Q\,} \,\overline S $$
C
$$P\,\overline {Q\,} \overline R + \overline P \,QR + PQRS + \overline {Q\,} \overline R \,\overline S $$
D
$$PQ\,\overline R + PQR\,\overline S + P\overline {Q\,} \overline R \,S + \overline {Q\,} \overline R \,\overline S $$
4
GATE ECE 2008
MCQ (Single Correct Answer)
+2
-0.6
Which of the follwing Boolean expression correctly represents the relation between P, Q, R and M1?

GATE ECE 2008 Digital Circuits - Logic Gates Question 11 English
A
M1=(P OR Q) XOR R
B
M1=(P AND Q) XOR R
C
M1=(P NOR Q) XOR R
D
M1=(P XOR Q) XOR R
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
CBSE
Class 12