IIT-JEE 2011 Paper 2 Offline | Electrostatics Question 46 | Physics

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IIT-JEE 2011 Paper 2 Offline

MCQ (More than One Correct Answer)

-1

Which of the following statement(s) is/are correct?

If the electric field due to a point charge varies as $${r^{ - 2.5}}$$ instead of $${r^{ - 2}},$$ then the Gauss law will still be valid.

The Gauss law can be used to calculate the field distribution around an electric dipole.

If the electric field between two point charges is zero somewhere, then the sign of the two charges is the same.

The work done by the external force in moving a unit positive charge from point $$A$$ at potential $${V_A}$$ to point $$B$$ at potential $${V_B}$$ is $$\left( {{V_B} - {V_A}} \right).$$

IIT-JEE 2011 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

A spherical metal shell A of radius $${R_A}$$ and a solid metal sphere $$B$$ of radius $${R_B}\left( { < {R_A}} \right)$$ are kept far apart and each is given charge $$' + Q'.$$ Now they are connected by a thin metal wire. Then

$$E_A^{inside} = 0$$

$${Q_A} > {Q_B}$$

$${{{\sigma _A}} \over {{\sigma _B}}} = {{{R_B}} \over {{R_A}}}$$

$$E_A^{on\,\,surface} < \,E_B^{on\,\,surface}$$

IIT-JEE 2010 Paper 1 Offline

MCQ (More than One Correct Answer)

-1

A few electric field lines for a system of two charges $${Q_1}$$ and $${Q_2}$$ fixed at two different points on the $$x$$-axis are shown in the figure. These lines suggest that

IIT-JEE 2010 Paper 1 Offline Physics - Electrostatics Question 58 English

IIT-JEE 2010 Paper 1 Offline Physics - Electrostatics Question 58 English

$$\left| {{Q_1}} \right| > \left| {{Q_2}} \right|$$

$$\left| {{Q_1}} \right| < \left| {{Q_2}} \right|$$

at a finite distance to the left of $${{Q_1}}$$ the electric field is zero

at a finite distance to the right of $${{Q_2}}$$ the electric field is zero

IIT-JEE 2006

MCQ (More than One Correct Answer)

-1

The electrostatic potential $\left(\phi_r\right)$ of a spherical symmetric system, kept at origin, is shown in the adjacent figure, and given as

$$ \begin{array}{ll} \phi_r=\frac{q}{4 \pi \epsilon_0 r} & \left(r \geq \mathrm{R}_0\right) \\ \phi_r=\frac{q}{4 \pi \epsilon_0 \mathrm{R}_0} & \left(r \leq \mathrm{R}_0\right) \end{array} $$

IIT-JEE 2006 Physics - Electrostatics Question 3 English

Which of the following option(s) is/are correct?

For spherical region $r \leq \mathrm{R}_0$, the total electrostatic energy stored is zero.

Within $r=2 \mathrm{R}_0$, the total charge is $q$.

There will be no charge anywhere except at $r=\mathrm{R}_0$.

Electric field is discontinuous at $r=\mathrm{R}_0$.

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