MHT CET 2026 19th April Evening Shift | Dual Nature of Radiation Question 5 | Physics

When light of wavelength '$\lambda$' is incident on a photosensitive surface, the stopping potential is 'V'. When a light of wavelength $1.5\lambda$ is incident on the same surface, the stopping potential is '$\dfrac{V}{4}$'. Threshold wavelength for the surface is

$\dfrac{6}{5}\lambda$

$\dfrac{7.5}{4}\lambda$

$\dfrac{7.5}{9}\lambda$

$\dfrac{9}{5}\lambda$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

A photoelectric surface is illuminated successively by monochromatic light of wavelength $\lambda$ and $(\lambda/3)$. If the maximum kinetic energy of the emitted photo electrons in the second case is $4$ times that in the first case, the work function of the surface of the material is ($h$ = Planck's constant, $c$ = speed of light)

$\dfrac{3hc}{\lambda}$

$\dfrac{hc}{3\lambda}$

$\dfrac{hc}{2\lambda}$

$\dfrac{hc}{\lambda}$

MHT CET 2026 19th April Morning Shift

MCQ (Single Correct Answer)

-0

According to Einstein's photoelectric equation, the graph of the kinetic energy of the emitted photoelectrons versus the frequency of incident radiation gives a straight line whose slope

depends on the intensity of incident radiation.

depends on the nature of the metal used.

is the same for all metals and independent of the intensity of radiation.

depends on both the intensity of incident radiation and the nature of metal used.

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

A photosensitive surface has work function $\phi$. If photon of energy $3 \phi$ falls on this surface, the electron comes out with maximum velocity of $4 \times 10^6 \mathrm{~m} / \mathrm{s}$ When photon energy is increased to $7 \phi$ then maximum velocity of photoelectron will be

$4 \sqrt{3} \times 10^6 \mathrm{~m} / \mathrm{s}$

$2 \sqrt{3} \times 10^6 \mathrm{~m} / \mathrm{s}$

$4 \sqrt{3} \times 10^3 \mathrm{~m} / \mathrm{s}$

$2 \sqrt{3} \times 10^3 \mathrm{~m} / \mathrm{s}$

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