MHT CET 2021 23th September Morning Shift | Dual Nature of Radiation Question 62 | Physics

When wavelength of incident radiation on the metal surface is reduced from '$$\lambda_1$$' to '$$\lambda_2$$', the kinetic energy of emitted photoelectrons is tripled. The work function of metal [$$\mathrm{h}=$$ Plank's constant, $$\mathrm{c}=$$ velocity of light]

$$\frac{\mathrm{hc}}{2}\left[\frac{3 \lambda_1-\lambda_2}{\lambda_1 \lambda_2}\right]$$

$$\frac{\mathrm{hc}}{2}\left[\frac{3 \lambda_2-\lambda_1}{\lambda_1 \lambda_2}\right]$$

hc $$\left[\frac{3 \lambda_1-\lambda_2}{\lambda_1 \lambda_2}\right]$$

hc $$\left[\frac{3 \lambda_2-\lambda_1}{\lambda_1 \lambda_2}\right]$$

MHT CET 2021 23th September Morning Shift

MCQ (Single Correct Answer)

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An electron of mass '$$m$$' and a photon have same energy '$$E$$'. The ratio of de-Broglie wavelength of electron to the wavelength of photon is $$(\mathrm{c}=$$ velocity of light)

$$c \sqrt{\frac{E}{m}}$$

$$\frac{1}{c} \sqrt{\frac{2 m}{g}}$$

$$\frac{1}{c} \sqrt{\frac{E}{2 m}}$$

$$c \sqrt{\frac{m}{E}}$$

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

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When a photon enters glass from air, which one of the following quantity does not change?

Energy

Velocity

Wavelength

Momentum

MHT CET 2021 22th September Evening Shift

MCQ (Single Correct Answer)

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The light of wavelength '$$\lambda$$' is incident on the surface of metal of work function $$\phi$$ and emits the electron. The maximum velocity of electron emitted is [$$\mathrm{m}=$$ mass of electron and $$\mathrm{h}=$$ Planck's constant, $$\mathrm{c}=$$ velocity of light]

$$\left[\frac{2(h c-\lambda)}{\mathrm{m} \lambda}\right]^{\frac{1}{2}}$$

$$\left[\frac{2(h c-\phi) \lambda}{m c}\right]$$

$$\left[\frac{2(h c-\lambda)}{m \lambda}\right]$$

$$\left[\frac{2(\mathrm{hc}-\lambda \phi)}{\mathrm{m} \lambda}\right]^{\frac{1}{2}}$$

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