MHT CET 2025 22nd April Morning Shift | Dual Nature of Radiation Question 4 | Physics

When a photosensitive metal surface is illuminated with radiation of wavelength ' $\lambda_1$ ', the stopping potential is ' $\mathrm{V}_1$ '. If the same surface is illuminated with radiation of wavelength ' $3 \lambda_1$ ', the stopping potential is $\frac{\mathrm{V}_1}{6}$. The threshold wavelength for the photosensitive metal surface is

$\frac{3}{2} \lambda_1$

$2 \lambda_1$

$5 \lambda_1$

$6 \lambda_1$

MHT CET 2025 22nd April Morning Shift

MCQ (Single Correct Answer)

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From photoelectric effect experiment, select the correct statement.

Photoelectric effect can be explained using wave theory of light.

The maximum kinetic energy of a photoelectron depends on the intensity of incident light.

The stopping potential depends only on the work function of the metal.

The saturation current increases as the intensity of incident light increases.

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

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When photons of energies twice and thrice the work function of a metal are incident on the metal surface one after other, the maximum velocities of the photoelectrons emitted in the two cases are $V_1$ and $V_2$ respectively. The ratio $\mathrm{V}_1: \mathrm{V}_2$ is

$\sqrt{3}: \sqrt{2}$

$\sqrt{2}: 1$

$\sqrt{3}: 1$

$1: \sqrt{2}$

MHT CET 2025 21st April Evening Shift

MCQ (Single Correct Answer)

-0

When a light of wavelength $\lambda$ falls on the emitter of a photocell, maximum speed of emitted photoelectrons is V . If the incident wavelength is changed to $\frac{2 \lambda}{3}$, maximum speed of emitted photoelectrons will be :

$\sqrt{3} \mathrm{~V}$

$\frac{\mathrm{V}}{2}$

$\sqrt{\frac{3}{2}} \mathrm{~V}$

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