MHT CET 2024 3rd May Morning Shift | Dual Nature of Radiation Question 34 | Physics

The ratio of the wavelength of a photon of energy ' $E$ ' to that of the electron of same energy is ( $\mathrm{m}=$ mass of an electron, $\mathrm{c}=$ speed of light, $\mathrm{h}=$ Planck's constant)

$\sqrt{\frac{\mathrm{m}}{\mathrm{cE}}}$

$\sqrt{\frac{2 \mathrm{~m}}{\mathrm{cE}}}$

$c \sqrt{\frac{\mathrm{~m}}{\mathrm{E}}}$

$c \sqrt{\frac{2 m}{E}}$

MHT CET 2024 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

When photons of energy hv fall on a photosensitive surface of work function $\mathrm{E}_0$, photoelectrons of maximum energy $k$ are emitted. If the frequency of radiation is doubled the maximum kinetic energy will be equal to ( $\mathrm{h}=$ Planck's constant)

2 k

$\mathrm{k}+\mathrm{E}_0$

$\mathrm{k}+\mathrm{h} \nu$

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The number of photoelectrons emitted for light of frequency $v$ (higher than the threshold frequency $\left(v_0\right)$ is proportional to

threshold frequency $\left(v_0\right)$

intensity of light (I)

frequency of light (v)

work function $\left(\phi_0\right)$

MHT CET 2024 2nd May Evening Shift

MCQ (Single Correct Answer)

-0

The stopping potential for a photelectric emission process is 10 V . The maximum kinetic energy of the electrons ejected in the process is [Charge on electron $\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$ ]

$3.2 \times 10^{-19} \mathrm{~J}$

$1.6 \times 10^{-19} \mathrm{~J}$

$1.6 \times 10^{-18} \mathrm{~J}$

0 J

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