MHT CET 2023 9th May Morning Shift | Dual Nature of Radiation Question 53 | Physics

From a metallic surface photoelectric emission is observed for frequencies $$v_1$$ and $$v_2\left(v_1 > v_2\right)$$ of the incident light. The maximum values of the kinetic energy of the photoelectrons emitted in the two cases are in the ratio $$1: \mathrm{x}$$. Hence the threshold frequency of the metallic surface is

$$\frac{v_1-v_2}{x}$$

$$\frac{v_1-v_2}{x-1}$$

$$\frac{x v_1-v_2}{x-1}$$

$$\frac{x v_2-v_1}{x-1}$$

MHT CET 2022 11th August Evening Shift

MCQ (Single Correct Answer)

-0

If the kinetic energy of a free electron doubles, it's de Broglie wavelength ($$\lambda$$) changes by a factor

$$\frac{1}{\sqrt{2}}$$

$$\frac{1}{2}$$

$$\sqrt{2}$$

$$2$$

MHT CET 2021 24th September Evening Shift

MCQ (Single Correct Answer)

-0

A light of wavelength '$$\lambda$$' and intensity '$$\mathrm{I}$$' falls on photosensitive material. If '$$\mathrm{N}$$' photo electrons are emitted, each with kinetic energy 'E', then

$$\mathrm{E} \propto \mathrm{I}, \mathrm{N} \propto \lambda$$

$$\mathrm{E} \propto \mathrm{I}, \mathrm{N} \propto \mathrm{I}$$

$$\mathrm{E} \propto \mathrm{I}, \mathrm{N} \propto \frac{1}{\lambda}$$

$$\mathrm{E} \propto \frac{1}{\lambda}, \mathrm{N} \propto \mathrm{I}$$

MHT CET 2021 24th September Evening Shift

MCQ (Single Correct Answer)

-0

In a photoelectric experiment, a graph of maximum kinetic energy $$(\mathrm{KE}_{\text {max }})$$ against the frequency of incident radiation (v) is plotted. If $$\mathrm{A}$$ and $$\mathrm{B}$$ are the intercepts on the $$\mathrm{X}$$ and $$\mathrm{Y}$$ axis respectively then the Planck's constant is given by

$$\mathrm{A}+\mathrm{B}$$

$$\frac{B}{A^{\prime}}$$

$$\mathrm{A} \times \mathrm{B}$$

$$\frac{\mathrm{A}}{\mathrm{B}}$$

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