MHT CET 2023 11th May Morning Shift | Dual Nature of Radiation Question 13 | Physics

The maximum kinetic energies of photoelectrons emitted are $$\mathrm{K}_1$$ and $$\mathrm{K}_2$$ when lights of wavelengths $$\lambda_1$$ and $$\lambda_2$$ are incident on a metallic surface. If $$\lambda_1=3 \lambda_2$$ then

$$\mathrm{K}_1=\frac{\mathrm{K}_2}{3}$$

$$\mathrm{K}_1<\frac{\mathrm{K}_2}{3}$$

$$\mathrm{K}_1=3 \mathrm{K}_2$$

$$3 \mathrm{K}_1=2 \mathrm{K}_2$$

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

If the potential difference used to accelerate electrons is doubled, by what factor does the de-Broglie wavelength associated with electrons change?

Wavelength in increased to $$\frac{1}{\sqrt{2}}$$ times.

Wavelength in increased to $$\frac{1}{2}$$ times.

Wavelength in decreased to $$\frac{1}{\sqrt{2}}$$ times.

Wavelength in decreased to $$\frac{1}{2}$$ times.

MHT CET 2023 10th May Evening Shift

MCQ (Single Correct Answer)

-0

The maximum kinetic energy of the photoelectrons varies

inversely with the intensity of incident radiation and is independent of its frequency.

inversely with the frequency of incident radiation and is independent on its intensity.

linearly with the frequency of incident radiation and depends on its intensity

linearly with the frequency of incident radiation and is independent of its intensity.

MHT CET 2023 10th May Morning Shift

MCQ (Single Correct Answer)

-0

An electron accelerated through a potential difference '$$V_1$$' has a de-Broglie wavelength '$$\lambda$$'. When the potential is changed to '$$V_2$$' its de-Broglie wavelength increases by $$50 \%$$. The value of $$\left(\frac{\mathrm{V}_1}{\mathrm{~V}_2}\right)$$ is

$$3: 1$$

$$9: 4$$

$$3: 2$$

$$4: 1$$

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