MHT CET 2025 19th April Evening Shift | Dual Nature of Radiation Question 3 | Physics

An electron accelerated by a potential difference ' $V$ ' has de-Broglie wavelength ' $\lambda$ '. If the electron is accelerated by a potential difference ' 9 V ', its de-Broglie wavelength will be

$\frac{\lambda}{4.5}$

$\frac{\lambda}{3}$

$\frac{\lambda}{2}$

$\lambda$

MHT CET 2025 19th April Evening Shift

MCQ (Single Correct Answer)

-0

The maximum velocity of the photoelectrons emitted by a metal surface is $9 \times 10^5 \mathrm{~m} / \mathrm{s}$. The value of ratio of charge (e) to mass (m) of the photoelectron is $1.8 \times 10^{11} \mathrm{C} / \mathrm{kg}$. The value of stopping potential in volt is

2.00

2.25

2.50

3.00

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

Light of wavelength $\lambda$ strikes a photoelectric surface and electrons are ejected with energy E . If $E$ is to be increased to twice the original value, the wavelength changes to $\lambda_1$

$\lambda_1<\lambda / 2$

$\lambda_1=\lambda$

$\lambda_1>\lambda / 2$

$\lambda_1=\lambda / 2$

MHT CET 2025 19th April Morning Shift

MCQ (Single Correct Answer)

-0

In a photoelectric experiment, if the intensity of incident light is doubled and the frequency is kept slightly greater than threshold frequency, then the saturation photoelectric current

remains constant

is halved

is doubled

becomes four times

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