MHT CET 2026 20th April Morning Shift | Dual Nature of Radiation Question 3 | Physics

The proton and $\alpha$ - particle are accelerated through same potential difference. Then the ratio of the de-Broglie wavelength of proton and $\alpha$ - particle is (mass of $\alpha$-particle is $4$ times mass of proton, charge of $\alpha$-particle is $2$ times charge of proton)

$3\sqrt{3}$

$3\sqrt{2}$

$2\sqrt{3}$

$2\sqrt{2}$

MHT CET 2026 20th April Morning Shift

MCQ (Single Correct Answer)

-0

Two identical photocathodes receive light of frequencies $n_1$ and $n_2$. If the velocities of the emitted photoelectrons of mass m are $V_1$ and $V_2$ respectively, then ($h$ = Planck's constant)

$V_1 + V_2 = \left[\dfrac{2h}{m}(n_1 + n_2)\right]^{\frac{1}{2}}$

$V_1 - V_2 = \left[\dfrac{2h}{m}(n_1 - n_2)\right]^{\frac{1}{2}}$

$V_1^2 + V_2^2 = \dfrac{2h}{m}(n_1 + n_2)$

$V_1^2 - V_2^2 = \dfrac{2h}{m}(n_1 - n_2)$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

A photosensitive surface has work function $\phi$. If photon of energy $3 \phi$ falls on this surface, the electron comes out with maximum velocity of $4 \times 10^6 \mathrm{~m} / \mathrm{s}$ When photon energy is increased to $7 \phi$ then maximum velocity of photoelectron will be

$4 \sqrt{3} \times 10^6 \mathrm{~m} / \mathrm{s}$

$2 \sqrt{3} \times 10^6 \mathrm{~m} / \mathrm{s}$

$4 \sqrt{3} \times 10^3 \mathrm{~m} / \mathrm{s}$

$2 \sqrt{3} \times 10^3 \mathrm{~m} / \mathrm{s}$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

Energy of the incident photons on the metal surface is initially 4 W and then 6 W where $W$ is the work function of that metal. The ratio of velocities of emitted photoelectrons is

$\sqrt{3}: \sqrt{5}$

$1: 2$

$2: 3$

$\sqrt{2}: \sqrt{3}$

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