MHT CET 2023 14th May Evening Shift | Dual Nature of Radiation Question 34 | Physics

When radiation of wavelength '$$\lambda$$' is incident on a metallic surface, the stopping potential is 4.8 V. If the surface is illuminated with radiation of double the wavelength then the stopping potential becomes $$1.6 \mathrm{~V}$$. The threshold wavelength for the surface is

$$2 \lambda$$

$$4 \lambda$$

$$6 \lambda$$

$$8 \lambda$$

MHT CET 2023 14th May Morning Shift

MCQ (Single Correct Answer)

-0

The de-Broglie wavelength $$(\lambda)$$ of a particle is related to its kinetic energy (E) as

$$\lambda \propto \mathrm{E}$$

$$\lambda \propto \mathrm{E}^{-1}$$

$$\lambda \propto \mathrm{E}^{\frac{1}{2}}$$

$$\lambda \propto \mathrm{E}^{-\frac{1}{2}}$$

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

Dual nature of light is exhibited by

diffraction as well as photoelectric effect

diffraction as well as reflection

refraction as well as interference

photoelectric effect

MHT CET 2023 13th May Evening Shift

MCQ (Single Correct Answer)

-0

When radiations of wavelength $$\lambda$$ is incident on a metallic surface the stopping potential required is $$4.8 \mathrm{~V}$$. If same surface is illuminated with radiations of double the wavelength, then required stopping potential becomes $$1.6 \mathrm{~V}$$, then the value of threshold wavelength for the surface is

$$2 \lambda$$

$$4 \lambda$$

$$6 \lambda$$

$$8 \lambda$$

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