1
IIT-JEE 2012 Paper 1 Offline
MCQ (Single Correct Answer)
+4
-1
Two large vertical and parallel metal plates having a separation of $$1$$ $$cm$$ are connected to a $$DC$$ voltage source of potential difference $$X$$. A proton is released at rest midway between the two plates. It is found to move at $${45^ \circ }$$ to the vertical JUST after release. Then $$X$$ is nearly
A
$$1 \times {10^{ - 5}}\,\,V$$
B
$$1 \times {10^{ - 7}}\,\,V$$
C
$$1 \times {10^{ - 9}}\,\,V$$
D
$$1 \times {10^{ - 10}}\,\,V$$
2
IIT-JEE 2011 Paper 1 Offline
MCQ (Single Correct Answer)
+2
-0.5
Consider an electric field $$\overrightarrow E = {E_0}\widehat x$$ where $${E_0}$$ is a constant. The flux through the shaded area (as shown in the figure) due to this field is
IIT-JEE 2011 Paper 1 Offline Physics - Electrostatics Question 57 English
A
$$2{E_0}{a_2}$$
B
$$\sqrt 2 {E_0}{a^2}$$
C
$${E_0}\,{a^2}$$
D
$${{{E_0}{a^2}} \over {\sqrt 2 }}$$
3
IIT-JEE 2011 Paper 2 Offline
MCQ (Single Correct Answer)
+2
-0.5
Which of the field patterns given below is valid for electric field as well as for magnetic field ?
A
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 1
B
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 2
C
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 3
D
IIT-JEE 2011 Paper 2 Offline Physics - Electrostatics Question 56 English Option 4
4
IIT-JEE 2010 Paper 2 Offline
MCQ (Single Correct Answer)
+2
-0.5
A tiny spherical oil drop carrying a net charge $$q$$ is balanced in still air with a vertical uniform electric field of strength $${{81\pi } \over 7} \times {10^5}\,\,V{m^{ - 1}}.$$ When the field is switched off, the drop is observed to fall with terminal velocity $$2 \times {10^{ - 3}}\,\,m{s^{ - 1}}.$$ Given $$g = 9.8\,m\,{s^{ - 2}},$$ viscosity of the air $$ = 1.8 \times {10^{ - 5}}\,\,Ns\,{m^{ - 2}}$$ and the density of coil $$=900$$ $$kg$$ $${m^{ - 3}},$$ the magnitude of $$q$$ is
A
$$1.6 \times {10^{ - 19}}C$$
B
$$3.2 \times {10^{ - 19}}C$$
C
$$4.8 \times {10^{ - 19}}C$$
D
$$8.0 \times {10^{ - 19}}C$$
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