List - A | List - B | |||
---|---|---|---|---|
P. | dsp2 | 1. | [FeF6]4- | |
Q. | sp3 | 2. | [Ti(H2O)3Cl3] | |
R. | sp3d2 | 3. | [Cr(NH3)6]3+ | |
S. | d2sp3 | 4. | [FeCl4]2- | |
5. | Ni(CO)4 | |||
6. | [Ni(CN)4]2- |
Among [Ni(CO)4], [NiCl4]2$$-$$, [Co(NH3)4)Cl2], Na3[CoF6], Na2O2 and CsO2, the total number of paramagnetic compound is
Match each coordination compound in List I with an appropriate pair of characteristics from List II and select the correct answer using the code given below the lists.
{en = H2NCH2CH2NH2; atomic numbers : Ti = 22, Cr = 24; Co = 27; Pt = 78}
List I | List II | ||
---|---|---|---|
P. | $$[Cr{(N{H_3})_3}C{l_2}]Cl$$ |
1. | Paramagnetic and exhibits ionisation isomerism. |
Q. | $$[Ti{({H_2}O)_5}Cl]{(N{O_3})_2}$$ |
2. | Diamagnetic and exhibits cis-trans isomerism. |
R. | $$[Pt(en)(N{H_3})Cl]N{O_3}$$ |
3. | Paramagnetic and exhibits cis-trans isomerism. |
S. | $$[Co{(N{H_3})_4}{(N{O_3})_2}]N{O_3}$$ |
4. | Diamagnetic and exhibits ionisation isomerism. |
For [Cr(NH3)4Cl2]Cl,
For [Ti(H2O)5Cl](NO3)2,
The complex is paramagnetic due to presence of unpaired electron.
Since the groups between the complex ion and ions outside can be exchanged, it shows ionisation isomerism.
For [Pt(en)(NH3)Cl]NO3,
The complex is square planar and all electrons are paired. So it is diamagnetic. Since the groups between the complex ion and ions outside can be exchanged, it shows ionisation isomerism.
For [Co(NH3)4(NO3)2]NO3, NH3 is a strong ligand and causes pairing