1
JEE Advanced 2026 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1

For a reversible reaction $R \rightleftharpoons P$, at constant temperature, both the forward and the backward reactions are first order elementary reactions with rate constants $k_{{f}}$ and $k_{{b}}$, respectively. At time zero, the concentration of $R$ is $[R]_0$ and the concentration of $P$ is zero. At any given time, $[R]$ and $[P]$ are the concentrations of $R$ and $P$, respectively. If $k_{{b}} = 4k_{{f}}$, the correct graphical representation of the reaction is

A
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 1
B
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 2
C
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 3
D
JEE Advanced 2026 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 2 English Option 4
2
JEE Advanced 2022 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

Match the rate expressions in LIST-I for the decomposition of $X$ with the corresponding profiles provided in LIST-II. $X_{\mathrm{s}}$ and $\mathrm{k}$ are constants having appropriate units.

List-I List-II
(I) rate $=\frac{\mathrm{k}[\mathrm{X}]}{\mathrm{X}_{\mathrm{s}}+[\mathrm{X}]}$

under all possible initial concentrations of $\mathrm{X}$
(P) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 16 English 1
(II) rate $=\frac{k[X]}{X_{s}+[X]}$

where initial concentrations of $X$ are much less than $X_{s}$
(Q) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 16 English 2
(III) rate $=\frac{k[X]}{X_{s}+[X]}$

where initial concentrations of $\mathrm{X}$ are much higher than $X_{s}$
(R) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 16 English 3
(IV) rate $=\frac{k[X]^{2}}{X_{s}+[X]}$

where initial concentration of $X$ is

much higher than $\mathrm{X}_{\mathrm{s}}$
(S) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 16 English 4
(T) JEE Advanced 2022 Paper 1 Online Chemistry - Chemical Kinetics and Nuclear Chemistry Question 16 English 5

A
$\mathrm{I} \rightarrow \mathrm{P}$; II $\rightarrow$ Q; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{T}$
B
$\mathrm{I} \rightarrow \mathrm{R}$; II $\rightarrow \mathrm{S}$; III $\rightarrow \mathrm{S}$; IV $\rightarrow \mathrm{T}$
C
$\mathrm{I} \rightarrow \mathrm{P}$; II $\rightarrow$ Q; III $\rightarrow$ Q; IV $\rightarrow$ R
D
$\mathrm{I} \rightarrow \mathrm{R}$; II $\rightarrow \mathrm{S}$; III $\rightarrow$ Q; IV $\rightarrow \mathrm{R}$
3
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1
For the elementary reaction M $$\to$$ N, the rate of disappearance of M increases by a factor of 8 upon doubling the concentration of M. The order of the reaction with respect to M is
A
4
B
3
C
2
D
1
4
JEE Advanced 2014 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-1

X and Y are two volatile liquids with molar weights of 10 g mol$$-$$1 and 40 g mol$$-$$1, respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.

JEE Advanced 2014 Paper 2 Offline Chemistry - Chemical Kinetics and Nuclear Chemistry Question 20 English Comprehension

The value of d in cm (shown in the figure), as estimated from Graham's law, is
A
8
B
12
C
16
D
20

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