1
JEE Advanced 2022 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
The correct option(s) about entropy (S) is(are)
$[\mathrm{R}=$ gas constant, $\mathrm{F}=$ Faraday constant, $\mathrm{T}=$ Temperature $]$
$[\mathrm{R}=$ gas constant, $\mathrm{F}=$ Faraday constant, $\mathrm{T}=$ Temperature $]$
2
JEE Advanced 2021 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-2
An ideal gas undergoes a reversible isothermal expansion from state I to state II followed by a reversible adiabatic expansion from state II to state III. The correct plot(s) representing the changes from state I to state III is (are)
(p : pressure, V : volume, T : temperature, H : enthalpy, S : entropy)
(p : pressure, V : volume, T : temperature, H : enthalpy, S : entropy)
3
JEE Advanced 2020 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-2
In thermodynamics, the p-V work done is given by
$$w = - \int {dV{p_{ext}}} $$
For a system undergoing a particular process, the work done is
$$w = - \int {dV\left( {{{RT} \over {V - b}} - {a \over {{V^2}}}} \right)} $$
This equation is applicable to a
$$w = - \int {dV{p_{ext}}} $$
For a system undergoing a particular process, the work done is
$$w = - \int {dV\left( {{{RT} \over {V - b}} - {a \over {{V^2}}}} \right)} $$
This equation is applicable to a
4
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Choose the reaction(s) from the following options, for which the standard enthalpy of reaction of equal to the standard enthalpy of formation.
Questions Asked from Thermodynamics (MCQ (Multiple Correct Answer))
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