1
JEE Advanced 2022 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language

LIST-I contains metal species and LIST-II contains their properties.

List-I List-II
(I) $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{4-}$
(P) $t_{2 \mathrm{g}}$ orbitals contain 4 electrons
(II) $\left[\mathrm{RuCl}_{6}\right]^{2-}$ (Q) $\mu$ (spin-only $)=4.9 \mathrm{BM}$
(III) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$
(R) low spin complex ion
(IV) $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$
(S) metal ion in $4+$ oxidation state
(T) $d^{4}$ species

[Given: Atomic number of $\mathrm{Cr}=24, \mathrm{Ru}=44, \mathrm{Fe}=26$ ]

Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option

A
I $\rightarrow$ R, T; II $\rightarrow$ P, S; III $\rightarrow$ Q, T; IV $\rightarrow$ P, Q
B
I $\rightarrow$ R, S; II $\rightarrow$ P, T; III $\rightarrow$ P, Q; IV $\rightarrow$ Q, T
C
I $\rightarrow$ P, R; II $\rightarrow$ R, S; III $\rightarrow$ R, T; IV $\rightarrow$ P, T
D
I $\rightarrow$ Q, T; II $\rightarrow$ S, T; III $\rightarrow$ P, T; IV $\rightarrow$ Q, R
2
JEE Advanced 2021 Paper 1 Online
MCQ (Single Correct Answer)
+3
-1
Change Language
The calculated spin only magnetic moments of [ Cr(NH3)6]3+ and [CuF6]3$$-$$ in BM, respectively, are

(Atomic numbers of Cr and Cu are 24 and 29, respectively)
A
3.87 and 2.84
B
4.90 and 1.73
C
3.87 and 1.73
D
4.90 and 2.84
3
JEE Advanced 2018 Paper 2 Offline
MCQ (Single Correct Answer)
+3
-0.75
Match each set of hybrid orbitals from LIST - A with complex(es) given in LIST - B

List - A List - B
P. dsp2 1. [FeF6]4-
Q. sp3 2. [Ti(H2O)3Cl3]
R. sp3d2 3. [Cr(NH3)6]3+
S. d2sp3 4. [FeCl4]2-
5. Ni(CO)4
6. [Ni(CN)4]2-

The correct option is
A
$$P - 5;Q - 4,6;R - 2,3;S - 1$$
B
$$P - 5,6;Q - 4;R - 3;S - 1,2$$
C
$$P - 6;Q - 4,5;R - 1;S - 2,3$$
D
$$P - 4,6;Q - 5,6;R - 1,2;S - 3$$
4
JEE Advanced 2016 Paper 1 Offline
MCQ (Single Correct Answer)
+3
-1

Among [Ni(CO)4], [NiCl4]2$$-$$, [Co(NH3)4)Cl2]Cl, Na3[CoF6], Na2O2 and CsO2, the total number of paramagnetic compound is

A
2
B
3
C
4
D
5
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