1
JEE Advanced 2026 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-1

In the following reaction sequence, P, Q, S and T are the major products.

JEE Advanced 2026 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 1 English

The correct statement(s) about P, Q, S and T is(are) :

A

Q on treatment with ethanol generates an aromatic aldehyde.

B

S gives positive phthalein dye test.

C

P is a dinitro compound.

D

T is a coloured compound.

2
JEE Advanced 2025 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

For the reaction sequence given below, the correct statement(s) is(are):

JEE Advanced 2025 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 7 English
A

Both X and Y are oxygen containing compounds.

B

Y on heating with CHCl$_3$/KOH forms isocyanide.

C

Z reacts with Hinsberg’s reagent.

D

Z is an aromatic primary amine.

3
JEE Advanced 2024 Paper 2 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

The option(s) with correct sequence of reagents for the conversion of $\mathbf{P}$ to $\mathbf{Q}$ is(are)

JEE Advanced 2024 Paper 2 Online Chemistry - Compounds Containing Nitrogen Question 11 English
A

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iii) $\mathrm{NaBH}_4$;

iv) $\mathrm{H}_3 \mathrm{O}^{+}$

B

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{H}_3 \mathrm{O}^{+}$;

iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iv) $\mathrm{NaBH}_4$

C

i) $\mathrm{NaBH}_4$;

ii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iii) $\mathrm{H}_3 \mathrm{O}^{+}$;

iv) Lindlar's catalyst, $\mathrm{H}_2$

D

i) Lindlar's catalyst, $\mathrm{H}_2$;

ii) $\mathrm{NaBH}_4$;

iii) $\mathrm{SnCl}_2 / \mathrm{HCl}$;

iv) $\mathrm{H}_3 \mathrm{O}^{+}$

4
JEE Advanced 2022 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

Considering the following reaction sequence,

JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 21 English

the correct option(s) is(are)

A
$\mathbf{P}=\mathrm{H}_{2} / \mathrm{Pd}$, ethanol     $\mathbf{R}=\mathrm{NaNO}_{2} / \mathrm{HCl}$      
$\mathbf{U}=1 . \mathrm{H}_{3} \mathrm{PO}_{2}$
         2. $\mathrm{KMnO}_{4}-\mathrm{KOH}$, heat
B
JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 21 English Option 2
C
JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 21 English Option 3
D
JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 21 English Option 4

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