Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option.

[Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25, \mathrm{Co}=27$ ]

List - I	List - II
(P) $t_{2 g}^6 e_g^0$	(1) $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$
(Q) $t_{2 g}^3 e_g^2$	(2) $\left[\mathrm{Mn}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}$
(R) $\mathrm{e}^2 \mathrm{t}_2^3$	(3) $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]^{3+}$
(S) $t_{2 g}^4 e_g^2$	(4) $\left[\mathrm{FeCl}_4\right]^{-}$
	(5) $\left[\mathrm{CoCl}_4\right]^{2-}$

LIST-I contains metal species and LIST-II contains their properties.

List-I	List-II
(I) $\left[\mathrm{Cr}(\mathrm{CN})_{6}\right]^{4-}$	(P) $t_{2 \mathrm{g}}$ orbitals contain 4 electrons
(II) $\left[\mathrm{RuCl}_{6}\right]^{2-}$	(Q) $\mu$ (spin-only $)=4.9 \mathrm{BM}$
(III) $\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$	(R) low spin complex ion
(IV) $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$	(S) metal ion in $4+$ oxidation state
	(T) $d^{4}$ species

[Given: Atomic number of $\mathrm{Cr}=24, \mathrm{Ru}=44, \mathrm{Fe}=26$ ]

Match each metal species in LIST-I with their properties in LIST-II, and choose the correct option

The calculated spin only magnetic moments of [ Cr(NH₃)₆]³⁺ and [CuF₆]3^$$-$$ in BM, respectively, are

(Atomic numbers of Cr and Cu are 24 and 29, respectively)

Match each set of hybrid orbitals from LIST - A with complex(es) given in LIST - B

	List - A			List - B
P.	dsp2		1.	[FeF6]4-
Q.	sp3		2.	[Ti(H2O)3Cl3]
R.	sp3d2		3.	[Cr(NH3)6]3+
S.	d2sp3		4.	[FeCl4]2-
			5.	Ni(CO)4
			6.	[Ni(CN)4]2-

The correct option is