MHT CET 2020 16th October Evening Shift | Dual Nature of Radiation Question 81 | Physics

The graph of kinetic energy against the frequency $$v$$ of incident light is as shown in the figure. The slope of the graph and intercept on $$X$$-axis respectively are

MHT CET 2020 16th October Evening Shift Physics - Dual Nature of Radiation Question 39 English

maximum KE threshold frequency

Planck's constant, threshold frequency

Planck's constant, work function

work function, maximum KE

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

The maximum velocity of the photoelectron emitted by the metal surface is $$v$$. Charge and mass of the photoelectron is denoted by $$e$$ and $$m$$, respectively. The stopping potential in volt is

$$\frac{v^2}{2\left(\frac{e}{m}\right)}$$

$$\frac{v^2}{\left(\frac{m}{e}\right)}$$

$$\frac{v^2}{2\left(\frac{m}{e}\right)}$$

$$\frac{v^2}{\left(\frac{e}{m}\right)}$$

MHT CET 2020 16th October Morning Shift

MCQ (Single Correct Answer)

-0

Energy of the incident photon on the metal surface is $$3 W$$ and then $$5 W$$, where $$W$$ is the work function for that metal. The ratio of velocities of emitted photoelectrons is

$$1: 4$$

$$1: 2$$

$$1: \sqrt{2}$$

$$1: 1$$

MHT CET 2019 3rd May Morning Shift

MCQ (Single Correct Answer)

-0

The stopping potential of the photoelectrons, from a photo cell is

directly proportional to intensity of incident light

directly proportional to frequency of incident light

inversely proportional to frequency of incident light

Inversely proportional to intensity of incident light

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