Match the compounds in Column I with their characteristic test(s)/reaction(s) given in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 $$\times$$ 4 matrix given in the ORS.
| Column I | Column II | ||
|---|---|---|---|
| (A) | ![]() |
(P) | sodium fusion extract of the compound gives Prussian blue colour with FeSO$$_4$$. |
| (B) | ![]() |
(Q) | gives positive FeCl$$_3$$ test. |
| (C) | ![]() |
(R) | gives white precipitate with AgNO$$_3$$. |
| (D) | ![]() |
(S) | reacts with aldehydes to form the corresponding hydrazone derivative. |
$\mathrm{CH}_3 \mathrm{NH}_2+\mathrm{CHCl}_3+\mathrm{KOH} \rightarrow$ Nitrogen containing compound $+\mathrm{KCl}+\mathrm{H}_2 \mathrm{O}$.
Nitrogen containing compound is :
$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.

In this reaction, RCONHBr is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
How can the conversion of (i) to (ii) be brought about?
$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.

In this reaction, RCONHBr is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
Which is the rate determining step in Hofmann bromamide degradation?
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