IIT-JEE 2009 Paper 2 Offline

MCQ (More than One Correct Answer)

-2

A sphere is rolling without slipping on a fixed horizontal plane surface. In the figure below, A is the point of contact, B is the centre of the sphere and C is its topmost point. Then,

IIT-JEE 2009 Paper 2 Offline Physics - Rotational Motion Question 29 English

$${\overrightarrow V _C} - {\overrightarrow V _A} = 2({\overrightarrow V _B} - {\overrightarrow V _C})$$

$${\overrightarrow V _C} - {\overrightarrow V _B} = {\overrightarrow V _B} - {\overrightarrow V _A}$$

$$|{\overrightarrow V _C} - {\overrightarrow V _A}| = 2|{\overrightarrow V _B} - {\overrightarrow V _C}|$$

$$|{\overrightarrow V _C} - {\overrightarrow V _A}| = 4|{\overrightarrow V _B}|$$

IIT-JEE 2009 Paper 1 Offline

MCQ (More than One Correct Answer)

-2

If the resultant of all the external forces acting on a system of particles is zero, then from an inertial frame, one can surely say that

Linear momentum of the system does not change in time.

Kinetic energy of the system does not change in time.

Angular momentum of the system does not change in time.

Potential energy of the system does not change in time.

IIT-JEE 2006

MCQ (More than One Correct Answer)

-1

A solid cylinder of mass m and radius $r$ is rolling on rough inclined plane of inclination $\theta$. The coefficient of friction between the cylinder and incline is $\mu$. then

frictional force is always $\mu \mathrm{mg} \cos \theta$.

friction is a dissipative force.

by decreasing $\theta$, frictional force decreases.

friction opposes translation and supports rotation.

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