1
JEE Advanced 2025 Paper 1 Online
MCQ (More than One Correct Answer)
+4
-2
Change Language

A conducting square loop of side $L$, mass $M$ and resistance $R$ is moving in the $X Y$ plane with its edges parallel to the $X$ and $Y$ axes. The region $y \geq 0$ has a uniform magnetic field, $\vec{B}=B_0 \widehat{k}$. The magnetic field is zero everywhere else. At time $t=0$, the loop starts to enter the magnetic field with an initial velocity $v_0 \hat{\jmath} \mathrm{~m} / \mathrm{s}$, as shown in the figure. Considering the quantity $K=\frac{B_0^2 L^2}{R M}$ in appropriate units, ignoring self-inductance of the loop and gravity, which of the following statements is/are correct:

JEE Advanced 2025 Paper 1 Online Physics - Electromagnetic Induction Question 1 English

A

If $v_0 = 1.5KL$, the loop will stop before it enters completely inside the region of magnetic field.

B

When the complete loop is inside the region of magnetic field, the net force acting on the loop is zero.

C

If $v_0 = \frac{KL}{10}$, the loop comes to rest at $t = \left(\frac{1}{K}\right) \ln\left(\frac{5}{2}\right)$.

D

If $v_0 = 3KL$, the complete loop enters inside the region of magnetic field at time $t = \left(\frac{1}{K}\right) \ln\left(\frac{3}{2}\right)$.

2
JEE Advanced 2019 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
A conducting wire of parabolic shape, initially y = x2, is moving with velocity $$v = {v_0}\widehat i$$ in a non-uniform magnetic field $$B = {B_0}\left( {1 + {{\left( {{y \over L}} \right)}^\beta }} \right)\widehat k$$, as shown in figure. If V0, B0, L and $$\beta $$ are positive constants and $$\Delta $$$$\phi $$ is the potential difference developed between the ends of the wire, then the correct statement(s) is/are

JEE Advanced 2019 Paper 1 Offline Physics - Electromagnetic Induction Question 16 English
A
$$\left| {\Delta \phi } \right| = {4 \over 3}{B_0}{V_0}L$$ for $$\beta $$ = 2
B
$$\left| {\Delta \phi } \right|$$ remains the same if the parabolic wire is replaced by a straight wire, y =x initially, of length $$\sqrt 2 L$$
C
$$\left| {\Delta \phi } \right|$$ = $${1 \over 2}{B_0}{V_0}L$$ for $$\beta $$ = 0
D
$$\left| {\Delta \phi } \right|$$ is proportional to the length of the wire projected on the y-axis.
3
JEE Advanced 2018 Paper 1 Offline
MCQ (More than One Correct Answer)
+4
-1
Change Language
In the figure below, the switches $${S_1}$$ and $${S_2}$$ are closed simultaneously at $$t=0$$ and a current starts to flow in the circuit. Both the batteries have the same magnitude of the electromotive force (emf) and the polarities are as indicated in the figure. Ignore mutual inductance between the inductors. The current $$I$$ in the middle wire reaches its maximum magnitude $${I_{\max }}$$ at time $$t = \tau $$ . Which of the following statements is (are) true?

JEE Advanced 2018 Paper 1 Offline Physics - Electromagnetic Induction Question 18 English
A
$${I_{\max }} = {V \over {2R}}$$
B
$${I_{max}} = {V \over {4R}}$$
C
$$\tau = {L \over R}\ln 2$$
D
$$\tau = {{2L} \over R}\ln 2$$
4
JEE Advanced 2017 Paper 2 Offline
MCQ (More than One Correct Answer)
+4
-2
Change Language
A source of constant voltage V is connected to a resistance R and two ideal inductors L1 and L2 through a switch S as shown. There is no mutual inductance between the two inductors. The switch S is initially open. At t = 0, the switch is closed and current begins to flow. Which of the following options is/are correct?

JEE Advanced 2017 Paper 2 Offline Physics - Electromagnetic Induction Question 10 English
A
After a long time, the current through L1 will be $${V \over R}{{{L_2}} \over {{L_1} + {L_2}}}$$
B
After a long time, the current through L2 will be $${V \over R}{{{L_1}} \over {{L_1} + {L_2}}}$$
C
The ratio of the currents through L1 and L2 is fixed at all times (t > 0)
D
At t = 0, the current through the resistance R is $${V \over R}$$
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